簡單的Objective-C程序不工作

Question

int main (int argc, const char * argv[]) 
{ 

    NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init]; 

    int n, number, triangularNumber; 
    NSLog(@"What Triangular Number Do You Want?"); 
    scanf(@"%i", &number); 
    triangularNumber = 0; 

    for (n = 1; n <= number; ++n) 
     triangularNumber += n; 
     NSLog(@"Triangular Number %i is %i", number, triangularNumber); 

    [pool drain]; 
    return 0; 
} 

輸出當我寫一個整數是這樣的：

Triangular Number 0 is 0 

Answer 1

您的輸入數字爲0，並且for循環中的條件從1開始。因此，循環從不執行。

Answer 2

它應該是：

for (n = 1; n <= number; ++n) { 
     triangularNumber += n; 
     NSLog(@"Triangular Number %i is %i", number, triangularNumber); 
} 

在你寫的方式，解析爲：

for (n = 1; n <= number; ++n) { 
    triangularNumber += n; 
} 
NSLog(@"Triangular Number %i is %i", number, triangularNumber); 

而且由於輸入（數字）是0（如指示由印刷品提供）循環不會發生，但印刷線。