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我怎樣才能把這個2個表togheter放2 MySQL表恩秀在一起的結果一起
$result = mysql_query("SELECT * FROM berichten where fromm='$id' AND ontvanger = '$session->username' ORDER BY date ASC");
$result = mysql_query("SELECT * FROM berichten_send where fromm='$id' AND ontvanger = '$session->username' ORDER BY date ASC");
這是笏我試過,但不是不工作
$result = mysql_query("SELECT * FROM berichten LEFT JOIN berichten_send on berichten.id = berichten_send.id where fromm='$id' AND ontvanger = '$session->username' ORDER BY date ASC");
$number=mysql_num_rows($result);
while($row = mysql_fetch_array($result))
{
echo $row['msg'];
echo "<br>";
echo time_stamp($row['date']);
echo "<br>-----------------------<br>";
}
這取決於你想獲取結果數據。 – hjpotter92
返回的錯誤信息是什麼? – 2013-09-22 09:34:30
沒有結果。它也沒有錯誤 –