MySQL的計數結果UNION不重疊

Question

好了，所以我有查詢

(SELECT * FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC) 
UNION 
(SELECT * FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC) 
UNION 
(SELECT * FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC) 
LIMIT 0, 30 

，我會運行使用COUNT(*)同樣的事情沒有限制

(SELECT COUNT(*) FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC) 
UNION 
(SELECT COUNT(*) FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC) 
UNION 
(SELECT COUNT(*) FROM jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) ORDER BY ups DESC,downs ASC) 

基本上我想什麼do是得到總結果的數量（沒有限制），並且也得到有限的列表。

我遇到的問題是，當我運行計數查詢時，我得到的數字比我回來的結果更大。我猜測的原因是當我得到結果時，它會過濾出所有重疊的行，因爲計數只計算每個行，因爲我手動添加它們。

關於如何清理整個過程的任何想法？

此外，請注意，選擇語句的數量動態變化，但我希望有一種方法來獲得一個統計重複的帳戶。

謝謝。

Answer 1

這個怎麼樣了字數：

SELECT COUNT(DISTINCT Id) 
FROM (SELECT Id From jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) 
     UNION 
     SELECT Id From jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?) 
     UNION 
     SELECT Id From jokes WHERE flags < 5 AND (title LIKE ? OR joke LIKE ?)) t 

這應該給你獨特的計數，並且還注意到，我得到，因爲它是不值得計算的計數查詢擺脫秩序。