找出從當前日期前一年日期在JavaScript

Question

我需要從當前日期找出上年日期，然後在JavaScript中設置的minDate jQuery中的UIDatePicker

我的日期formaqt是dd-mm-yy

即

• 當前日期是25-07-2012
• 我需要得到25-07-2011

Answer 1

對於字符串：

curdate.substr(0, 6)+(curdate.substr(6)-1); 

如果你會使用一個Date object，你可以輕鬆減去一年與set[Full]Year方法。

Answer 2

您需要使用getFullYear()

，然後產生新的日期

var d = new Date(2012, 7, 25); 
d.setFullYear(d.getFullYear() - 1); 

Answer 3

使用此：

var date = new Date(); 
var intYear = date.getFullYear() - 1; 

Answer 4

，以免日後對象（如果這是OP希望）：

var currDate = '25-07-2012'; 
var dateParts = currDate.split('-'); 
dateParts[2] = parseInt(dateParts[2], 10) - 1; 
alert(dateParts.join('-'));​ 

Answer 5

Datepicker允許您將一個數字作爲minDate選項，並將其用作當前日期的偏移量。所以你可以寫：

minDate: -365 

指定1年前。不過，這並沒有考慮到閏年。

Answer 6

var today = new Date(); 
var curyear = today.getFullYear(); 
var curyearMonth = today.getMonth() + 1; 
var curyearDay = today.getDate(); 
var lastYear = curyear - 1; 
if ((curyearMonth == 2) && (curyearDay == 29)) { 
    curyearDay = 28; 
} 

var lastYearDisplay = ("0000" + lastYear.toString()).slice(-4) + "-" + ("00" + curyearMonth.toString()).slice(-2) + "-" + ("00" + curyearDay.toString()).slice(-2); 
alert("LastWeekDate : " + lastYearDisplay); 

Answer 7

var date = CALC.today(); //(function in my dev-enviro - gives today's date) 
var year = formatDate(date, 'yyyy'); //year is 2016 
year = parseInt(year);    //make sure '2016' becomes an integer 
year = year -1;      // var year is now: 2015. 

//its been a while, but that's what I did from memory. 

Answer 8

function getTodayDate() { 
     var today = new Date(); 
     var dd = today.getDate(); 
     var mm = today.getMonth() + 1; //January is not 0! 
     var yyyy = today.getFullYear(); 
     if (dd < 10) { dd = '0' + dd } 
     if (mm < 10) { mm = '0' + mm } 
     today = yyyy + '-' + mm + '-' + dd; 
     return today; 
    }; 
    function getYearAgo(){ 
    var lastYear = new Date(); 
    var dd = lastYear.getDate(); 
    var mm = lastYear.getMonth() + 1; //January is not 0! 
    var yyyy = lastYear.getFullYear(getTodayDate) - 1; 
    if (dd < 10) { dd = '0' + dd } 
    if (mm < 10) { mm = '0' + mm } 
    lastYear = yyyy + '-' + mm + '-' + dd;  
    return lastYear; 
    } 

Answer 9

試試這個

var d = new Date(); 
var pastYear = d.getFullYear() - 1; 
d.setFullYear(pastYear); 
console.log(d);