這個查詢不是有效的

Question

我有一個查詢字段，查詢兩個不同表格中的三個不同列：位置表中的「公司」和「行業」以及教育表中的「學校」。它已成功返回滿足在搜索字段中輸入的所有字段的所有用戶（使用select_tag）。這是從我的觀點：

<%= form_tag(search_path, :method => :get, :id => "people_search") do %> 
    <div class="row-fluid"> 
     <div class="span4"> 
     <table> 
      <tr> 
      <td> 
       <div class="search-table" style="padding-left:55px"> 
       <%= select_tag "all", options_for_select((@visible_companies + @visible_industries + @visible_schools).uniq, params[:all]), { :placeholder => "Search by companies, industries and schools...", :multiple => true, :js => "if (evt.keyCode == 13) {form.submit();}" } %> 
       </div> 
      </td> 
      <td> 
       <%= submit_tag "Add", id: "send-button", style:"width:175px;" %> 
      </td> 
      </tr> 
     </table> 
     </div> 
    <% end %> 
    </div> 

和控制器：

@visible_positions = Position.where{ is_visible.eq('true') } 
    @visible_educations = Education.where{ is_visible.eq('true') } 

    @visible_companies = @visible_positions.order("LOWER(company)").map(&:company).uniq 
    @visible_industries = @visible_positions.order("LOWER(industry)").map(&:industry).uniq 
    @visible_schools = @visible_educations.order("LOWER(school)").map(&:school).uniq 

    @c = @visible_positions.where{company.in(my{params[:all]})}.map(&:user_id) 
    @i = @visible_positions.where{industry.in(my{params[:all]})}.map(&:user_id) 
    @s = @visible_educations.where{school.in(my{params[:all]})}.map(&:user_id) 

    @C = @visible_positions.where{company.in(my{params[:all]})}.map(&:company) 
    @I = @visible_positions.where{industry.in(my{params[:all]})}.map(&:industry) 
    @S = @visible_educations.where{school.in(my{params[:all]})}.map(&:school) 

    @blacklist = []  
    @cis = @c + @i + @s 
    @experiences = ([@C,@I,@S].reject(&:empty?).reduce(:&)) 

    @cis.uniq.each do |user_id| 

     unless @C.empty? 
     @C.uniq.each do |company| 
      unless Position.find_all_by_company(company).map(&:user_id).include?(user_id) || Position.find_all_by_industry(company).map(&:user_id).include?(user_id) || Education.find_all_by_school(company).map(&:user_id).include?(user_id) 
      @blacklist << user_id 
      end 
     end 
     end 
     unless @I.empty? 
     @I.uniq.each do |industry| 
      unless Position.find_all_by_industry(industry).map(&:user_id).include?(user_id) || Position.find_all_by_company(industry).map(&:user_id).include?(user_id) || Education.find_all_by_school(industry).map(&:user_id).include?(user_id) 
      @blacklist << user_id 
      end 
     end 
     end 
     unless @S.empty? 
     @S.each do |school| 
      unless Education.find_all_by_school(school).map(&:user_id).include?(user_id) || Position.find_all_by_company(school).map(&:user_id).include?(user_id) || Position.find_all_by_industry(school).map(&:user_id).include?(user_id) 
      @blacklist << user_id 
      end 
     end 
     end 

    end 

    unless @c.empty? && @i.empty? && @s.empty? 
     @users = User.find(@cis - @blacklist) 
    end 

搜索看起來是這樣的（注意單場），與樣本查詢包括（注意和過濾...我」 M在適合所有的搜索字詞[「達特茅斯學院」學校，「世界衛生組織」的公司，爲行業的互聯網']）數據庫的唯一用戶：

我意識到這不是一個有效的查詢，並且正在考慮如何加速它，但是可以在這一點上使用一些想法。

快樂土耳其一天:)

Answer 1

根據您的描述而不是在理解你的代碼，我想通了，這樣的事情

User.joins(:positions, :educations).where("lower(positions.company) like lower(?) and lower(positions.industry) like lower(?) and lower(educations.school) like lower(?) and positions.is_visible and educations.is_visible", "%#{company}%", "%#{industry}%", "%#{school}%") 

，或者如果只有一個公司或行業中列

User.joins(:positions, :educations).where("(lower(positions.company) = lower(?) or lower(positions.industry) = lower(?)) and lower(educations.school) = lower(?) and positions.is_visible and educations.is_visible", company,industry, school) 

但是要把許多行業，公司，學校作爲參數會更復雜 並創建索引

create index positions_lower_company on positions (lower(company)); 
create index positions_lower_industry on positions (lower(industry)); 
create index educations_lower_school on educations (lower(school)); 

我希望這會有所幫助。