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因此,我正在製作一個隨機數的遊戲,你必須猜測它是什麼,但是,當它說你贏了,或者你失去了文本就停留在那裏,我不能弄清楚如何刪除舊文本。我試圖做screen.blit(背景,(0,0)),但它不會改變一件事。 (是的,我做了pygame.display.flip())我看遍了整個網絡(我首先檢查了堆棧溢出),但沒有成功。幫幫我!Pygame文本重疊
import random, pygame, pygbutton
from pygame.locals import *
pygame.init()
dice = random.randint(1, 6)
def window():
width = 600
height = 600
# background_color = (0, 0, 0)
WH = (width, height)
screen = pygame.display.set_mode(WH)
background = pygame.image.load("wood.jpg").convert()
background=pygame.transform.scale(background,(600, 600))
pygame.display.set_caption("Dice Game!")
screen.blit(background, (600, 600))
num1_button = pygbutton.PygButton((0, 0, 100,50), '1')
num2_button = pygbutton.PygButton((0, 50, 100, 50), '2')
# screen.fill(background_color)
font = pygame.font.Font(None, 100)
running = True
while running == True:
dice = random.randint(1, 6)
screen.blit(background, (0, 0))
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
if event.type == KEYDOWN:
if event.key == pygame.K_ESCAPE:
quit()
if 'click' in num1_button.handleEvent(event):
if dice == 1:
text = font.render("You Win!", 1, (0, 0, 0))
background.blit(text, (155, 255))
screen.blit(background, (0, 0))
else:
Text = font.render("You Lose!", 1, (0, 0, 0))
background.blit(Text, (155, 255))
screen.blit(background, (0, 0))
cliq = True
if 'click' in num2_button.handleEvent(event):
if dice == 2:
text = font.render("You Win!", 1, (0, 0, 0))
background.blit(text, (155, 255))
screen.blit(background, (0, 0))
else:
Text = font.render("You Lose!", 1, (0, 0, 0))
background.blit(Text, (155, 255))
screen.blit(background, (0, 0))
cliq=True
num1_button.draw(screen)
num2_button.draw(screen)
pygame.display.flip()
window()
如果您告訴我在哪裏放置更改,我也會喜歡它。先謝謝你!