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我已經建立了一個C＃服務器，它目前通過TCP提供一個測試mp3文件。發送文件的代碼如下從C＃服務器流式MP3到Android
public void RunStreamer()
{
log.MakeLog("Starting streamer");
Run = true;
//Need to look into how to thread this to not block the main window
TcpListener listen = new TcpListener(localAddr, _port);
listen.Start(); //startlistening to client requests
//blocks until a client request comes in
for (; ;)
{
Socket socket = listen.AcceptSocket();
if (socket.Connected)
{
SendFileToClient(socket);
socket.Disconnect(false);
}
}
}
void SendFileToClient(Socket socket)
{
log.MakeLog("Connection made");
NetworkStream netStream = new NetworkStream(socket);
StreamWriter writer = new StreamWriter(netStream);
//Todo - set specfified file - this file just for test
FileStream filestream = File.Open(@"C:\MusicTest\Test.mp3", FileMode.Open, FileAccess.Read, FileShare.Read);
filestream.CopyTo(netStream);
netStream.Flush();
netStream.Close();
}
在我的測試Android的設置我點擊一個按鈕向服務器的呼叫：
public void btngo_click(View v)
{
final TcpClient client = new TcpClient();
new Thread(new Runnable(){
@Override
public void run() {
final MediaPlayer mediaPlayer = new MediaPlayer();
client.GetStream();
runOnUiThread(new Runnable(){
public void run()
{
int length = client.GetLength();
if(length > 0)
{
byte[] result = client.GetResult();
try {
// create temp file that will hold byte array
File tempMp3 = File.createTempFile("test", "mp3", getCacheDir());
tempMp3.deleteOnExit();
FileOutputStream fos = new FileOutputStream(tempMp3);
fos.write(result);
fos.close();
mediaPlayer.reset();
FileInputStream fis = new FileInputStream(tempMp3);
mediaPlayer.setDataSource(fis.getFD());
mediaPlayer.prepare();
mediaPlayer.start();
} catch (IOException ex) {
String s = ex.toString();
ex.printStackTrace();
}
}
}
});
}
}).start();
}
流在TcpClient類接收這是如下：
public class TcpClient {
public final static String SERVER_ADDRESS = "127.0.0.1";
public final static int SERVER_PORT = 65000;
public String TotalResult;
public int Length;
byte[] result = new byte[21000000];
public TcpClient()
{
}
public int GetLength()
{
return Length;
}
public byte[] GetResult()
{
return result;
}
public void GetStream()
{
try
{
final Socket socket = new Socket("192.0.0.5", 85000);
final InputStream input = new BufferedInputStream(socket.getInputStream());
ByteArrayOutputStream buffer = new ByteArrayOutputStream();
int nread;
while((nread = input.read(result, 0, result.length)) != -1)
{
buffer.write(result, 0, nread);
}
buffer.flush();
//input.read(result);
Length = result.length;
input.close();
socket.close();
} catch (UnknownHostException e) {
String exc = e.getMessage();
e.printStackTrace();
} catch (IOException e) {
String exc2 = e.getMessage();
e.printStackTrace();
}
}
}
隨着道歉這裏所有的代碼是我的問題。
我正在接收流。臨時MP3文件已創建並且媒體播放器啓動。然後，我只能得到測試MP3文件的短片段（這是一首完整的歌曲）。它也跳了一下。長度不一樣，每次播放的歌曲部分都不相同。
如何以有序方式接收完整文件，以便能夠提供歌曲的完整播放。
我試圖繞過這一點，並有一個想法，我需要告訴我的客戶它應該懷疑什麼文件大小，然後執行一些循環，直到收到所有數據，雖然我不知道如何成功實現這個if這是正確的解決方案。
任何指向哪裏我錯了什麼或我可以做什麼來糾正將不勝感激！
我認爲這是通過Wi-Fi？ – MyCodeSucks 2013-02-28 22:26:49
是的，這是通過無線上網 - 我已經在模擬器上在桌面和手機上測試過，結果相同 – Luthervd 2013-02-28 22:36:55