功能不會產生圖像仍然像它通過

Question

確定這樣的問題似乎是在功能上沒有創建圖像，或在腳本它自其沒有圖像不傳遞給函數

這裏上傳腳本（注：這是注入AJAX）

$path = "cache/"; 

    $valid_formats = array("jpg", "png", "gif", "jpeg"); 
    if(isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST") 
     { 
     $name = $_FILES['photoimg']['name']; 
     $size = $_FILES['photoimg']['size']; 

     if(strlen($name)) 
       { 
       ist($txt, $ext) = explode(".", $name); 
       if(in_array($ext,$valid_formats)) 
       { 
       if($size<(2024*2024)) 
        { 
        $new_file = "header.".$ext; 
        $tmp = $_FILES['photoimg']['tmp_name']; 
        if(move_uploaded_file($tmp, $path.$new_file)) 
        { 

      echo "<img src='cache/".$new_file."?".time()."' class='preview'>"; 

       createHeader($new_file);         
        } 

        else 
        echo "failed"; 
        } 

        else 
        echo "Image file size max 1 MB";      
        } 
        else 
       echo "Invalid file format.."; 
       } 

      else 
       echo "Please select image..!"; 

      exit; 
     } 

現在這裏是功能

function createHeader($new_file) { 

$path = "uploads/"; 
$image = "cache/"; 
$width = 800; 

    if(preg_match('/[.](jpg)|(jpeg)$/', $new_file)) { 

     $im = imagecreatefromjpeg($image . $new_file); 

    } else if (preg_match('/[.](gif)$/', $new_file)) { 

     $im = imagecreatefromgif($image . $new_file); 
     imagecolortransparent($im, black);  

    } else if (preg_match('/[.](png)$/', $new_file)) { 

     $im = imagecreatefrompng($image . $new_file); 
    } 

    imagealphablending($im, false); 
    imagesavealpha($im, true); 

    $ox = imagesx($im); 
    $oy = imagesy($im); 

    $nx = $width; 
    $ny = floor($oy * ($width/$ox)); 

    imagecopyresampled($nm, $im, 0,0,0,0,$nx,$ny,$ox,$oy);  
    imagealphablending($im, true); 
    if(!file_exists($path)) { 
     if(!mkdir($path)) { 
      die("There was a problem. Please try again!"); 
     } 
     } 

    imagejpeg($nm, $path . $new_file, 100); 

    imagedestroy($im); 
    imagedestroy($nm); 

} 

在邏輯上什麼代碼必須是如果用戶使用我的CMS做的是loged，在他（她）可以更改標題在頁面上點擊一個圖標，這將使jQuery調用edit.php傳遞所需的查詢字符串。從那裏自己的用戶可以上傳一個新的圖像，它將被重命名爲header.jpg並覆蓋原始圖像

header.jpg必須上傳到uploads /目錄並且原始圖像緩存/應該是未鏈接的副本那些函數可以創建一個副本並將其放入uploads /目錄中。

發生了什麼事是第一個腳本正在上傳文件並將其放入緩存/目錄中，但該功能似乎不起作用，並且對上傳/目錄沒有任何作用。

任何想法我可能做錯了或不這樣做是造成這個惱人的問題？

Answer 1

$ path =「cache /」;

$valid_formats = array("jpg", "png", "gif", "jpeg"); 
if(isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST") 
    { 
    $name = $_FILES['photoimg']['name']; 
    $size = $_FILES['photoimg']['size']; 

    if(strlen($name)) 
      { 
      list($txt, $ext) = explode(".", $name); 
      if(in_array($ext,$valid_formats)) 
      { 
      if($size<(2024*2024)) 
       { 
       $new_file = "header.".$ext; 
       $tmp = $_FILES['photoimg']['tmp_name']; 
       if(move_uploaded_file($tmp, $path.$new_file)) 
       { 

      // This needs to happen before the echo of the image tag 
      createHeader($new_file);         

     echo "<img src='cache/".$new_file."?".time()."' class='preview'>"; 
       } 

       else 
       echo "failed"; 
       } 

       else 
       echo "Image file size max 1 MB";      
       } 
       else 
      echo "Invalid file format.."; 
      } 

     else 
      echo "Please select image..!"; 

     exit; 
    }