嘿,我還需要與評級系統幫助一點點,但如果cookie存在,這是檢查在PHP腳本中的cookie
<?php
$rating = new ratings($_POST['widget_id']);
isset($_POST['fetch']) ? $rating->get_ratings() : $rating->vote();
class ratings {
var $data_file = './ratings.data.txt';
private $widget_id;
private $data = array();
function __construct($wid) {
$this->widget_id = $wid;
$all = file_get_contents($this->data_file);
if($all) {
$this->data = unserialize($all);
}
}
public function get_ratings() {
if($this->data[$this->widget_id]) {
echo json_encode($this->data[$this->widget_id]);
}
else {
$data['widget_id'] = $this->widget_id;
$data['number_votes'] = 0;
$data['total_points'] = 0;
$data['dec_avg'] = 0;
$data['whole_avg'] = 0;
echo json_encode($data);
}
}
public function vote() {
# Get the value of the vote
preg_match('/star_([1-5]{1})/', $_POST['clicked_on'], $match);
$vote = $match[1];
$ID = $this->widget_id;
# Update the record if it exists
# doesn't update if it already exists
if (!isset($_COOKIE[$id])) {
if($this->data[$ID]) {
$this->data[$ID]['number_votes'] += 1;
$this->data[$ID]['total_points'] += $vote;
}
# Create a new one if it doesn't
else {
$this->data[$ID]['number_votes'] = 1;
$this->data[$ID]['total_points'] = $vote;
}
$this->data[$ID]['dec_avg'] = round($this->data[$ID]['total_points']/$this->data[$ID]['number_votes'], 1);
$this->data[$ID]['whole_avg'] = round($this->data[$ID]['dec_avg']);
file_put_contents($this->data_file, serialize($this->data));
$this->get_ratings();
}
} //ends if isset
# ---
# end class
}
?>
應該檢查是否cookie中的一部分,我有一個問題檢查存在是這樣的:
if (!isset($_COOKIE[$id])) {
但由於某種原因,當我添加該腳本的任何工作。
我沒有經歷所有的代碼,但你有一個可能導致問題的$ id和$ ID的混合。 – Sol