PHP imagejpeg無法正常工作

Question

所以我看了幾乎每個問題，並嘗試使用下面的PHP腳本來顯示我的圖像。但它不起作用。我也試着看看GD庫是否使用PHPInfo（）來啓用，並且它也可以工作。我對PHP很陌生，但似乎無法得到這個工作。謝謝你的幫助！

編輯︰我點擊上傳文檔按鈕後，我得到一個破碎的圖像圖標。

<?php 
if($_SERVER['REQUEST_METHOD'] == 'POST') { 
if(isset($_FILES['photo']) 
     && is_uploaded_file($_FILES['photo']['tmp_name']) 
     && $_FILES['photo']['error'] == UPLOAD_ERR_OK) { 
      foreach ($_FILES['photo'] as $key => $value) { 
       echo "$key : $value<br />"; 
      } 
      if($_FILES['photo']['type'] == 'image/jpeg') { 
       $tmp_img = $_FILES['photo']['tmp_name']; 
       $image = imagecreatefromjpeg($tmp_img); 
       header('Content-Type: image/jpeg'); 
       imagejpeg($image,NULL); 
       imagedestroy($image); 
      } else { 
       echo "Uploaded file ewas not a jpg image."; 
      } 
       echo "no photo uploaded."; 
       } 
} 
?> 
<form enctype="multipart/form-data" action="book.php" method="post"> 
<input type="file" name="photo"> 
<input type="submit" value="upload a doc"> 
</form> 

Answer 1

您可以嘗試imagedestroy($image);之後添加die();防止除了圖像數據的任何其他輸出。還將imagejpeg($image,NULL);更改爲imagejpeg($image);。

Answer 2

您無法直接訪問圖像tmp_name。首先，你應該將圖像保存到服務器後，您可以用imagecreatefromjpeg

<?php 
if($_SERVER['REQUEST_METHOD'] == 'POST') { 
if(isset($_FILES['photo']) 
     && is_uploaded_file($_FILES['photo']['tmp_name']) 
     && $_FILES['photo']['error'] == UPLOAD_ERR_OK) { 
      if($_FILES['photo']['type'] == 'image/jpeg') { 
       $tmp_img = $_FILES['photo']['tmp_name']; 
       $uniq_name = uniqid().".".explode(".",$tmp_img)[1]; 
       move_uploaded_file($_FILES['photo']['tmp_name'],$uniq_name); 
       $image = imagecreatefromjpeg($uniq_name); 
       header('Content-Type: image/jpeg'); 
       imagejpeg($image); 
       imagedestroy($image); 
      } else { 
       echo "Uploaded file ewas not a jpg image."; 
      } 
       echo "no photo uploaded."; 
       } 
} 
?> 
<form enctype="multipart/form-data" action="book.php" method="post"> 
<input type="file" name="photo"> 
<input type="submit" value="upload a doc"> 
</form> 

Answer 3

使用我認爲問題出在PHP部分（HTML代碼）後echo和輸出字符串。刪除foreach循環，並僅當它是新頁面或出現錯誤時才輸出HTML。

<?php 
    if($_SERVER['REQUEST_METHOD'] == 'POST') { 
    if(isset($_FILES['photo']) 
     && is_uploaded_file($_FILES['photo']['tmp_name']) 
     && $_FILES['photo']['error'] == UPLOAD_ERR_OK) { 
      if($_FILES['photo']['type'] == 'image/jpeg') { 
       $tmp_img = $_FILES['photo']['tmp_name']; 
       $image = imagecreatefromjpeg($tmp_img); 
       header('Content-Type: image/jpeg'); 
       imagejpeg($image,NULL); 
       imagedestroy($image); 
       exit; // Add this to stop the program here. 
      } else { 
       echo "Uploaded file was not a jpg image."; 
      } 
    } else { 
     echo 'No file was sent.'; 
    } 
} 
?> 
<form enctype="multipart/form-data" action="book.php" method="post"> 
<input type="file" name="photo"> 
<input type="submit" value="upload a doc"> 
</form> 

還有一件事，如果您使用記事本進行編碼，請確保文件開頭處沒有隱藏字符。