2016-03-21 167 views
0

我正在與PHP和MySQL(PHPMyAdmin中)一個註冊表格,當我打開瀏覽器(Mozilla Firefox瀏覽器)的頁面,我得到

Parse error: syntax error, unexpected $end in line 71

<?php 

require('config.php'); 

if(isset($_POST['submit'])){ 

    //Verificació 
    $email1 = $_POST['email1']; 
    $email2 = $_POST['email2']; 
    $pass1 = $_POST['pass1']; 
    $pass2 = $_POST['pass2']; 

    if($email1 == $email2){ 
     if ($pass1 == $pass2){ 
      //Tot bé! 

      $name = mysql_escape_string($_POST['name']); 
      $lname = mysql_escape_string($_POST['lname']); 
      $email1 = mysql_escape_string($email1); 
      $email2 = mysql_escape_string($email2); 
      $pass1 = mysql_escape_string($pass1); 
      $pass2 = mysql_escape_string($pass2); 



     }else{ 
      die("Sorry, your passwords didn't match"); 
     } 
    }else{ 
     die("Sorry, your emails didn't match"); 
    } 


}else{ 

    echo <<<EOD 

    <form action='register.php' method='POST'> 
    First name:<input type='text' name='name' /><br/> 
    Last name:<input type='text' name='lName' /><br/> 
    Username:<input type='text' name='username' /><br/> 
    Email:<input type='text' name='email' /><br/> 
    Password:<input type='password' name='pass1' /><br/> 
    Confirm password:<input type='password' name='pass2' /><br/> 
    <input type='submit' value='Register' name='submit' /> 
    </form> 
    EOD; 

} 

?> 

我在做什麼不好?有人能幫助我嗎?

回答