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我需要將表單的克隆區域傳遞給PHP,方法是將每個區域都添加到數組中。JQuery克隆選定區域並將所有內容傳遞給PHP Array
我的代碼
<div class="input-main white_bg cloneneedsanalysis">
<div class="action-input clone-needs-analysis">
<div class="action-input-white-shorter">
<div class="inner-sub-title-less-padding">
<p>Audience Analysis</p>
</div>
<div class="col-md-12">
<div class="form-group">
<select class="select2 select2-multiple" multiple="multiple" data-placeholder="Choose ..." name="needs_analysis[]">
<option value="">-- Choose Audience Categories --</option>
<option value="536"> Finance - - Cash collection </option>
<option value="537"> IT - - Comms IT </option>
<option value="538"> Strategy - - Strategy team 1 </option>
</select>
</div>
</div>
</div>
<div class="action-input-plus-needs-analysis"> </div>
<div class="action-input-remove-needs-analysis"> </div>
</div>
</div>
克隆的作品,但是當我發送通過POST給PHP將只捕獲最後一個,因爲他們都是所謂的叫needs_analysis []
那麼,克隆了當我可以編輯名稱,以便它不同,我怎樣才能讓PHP循環訪問每個數組?
My JQuery;
$(document).on('click', '.clone_needs_analysis_button', function(e) {
e.preventDefault();
$(this).closest('.clone-needs-analysis').clone().insertAfter('.cloneneedsanalysis:last');
$(this).closest('.action-input-plus').hide();
$(this).closest('.action-input-remove').removeClass('hidden');
我的PHP;
$needs_analysis = array();
foreach ($_POST['needs_analysis'] as $key => $value) {
$needs_analysis[$key]['audience_id'] = $value;
$needs_analysis[$key]['created'] = $_POST['updated'];
$needs_analysis[$key]['created_by'] = $_POST['updated_by'];
$needs_analysis[$key]['solution_id'] = $_POST['solution_id'];
}
foreach ($needs_analysis as $needs_analysis_insert) {
$db->insert('design_needs_analysis', $needs_analysis_insert);
}
你的其他輸入是哪裏來的? – madalinivascu