preg_replace insade paragprah添加錨鏈接

Question

我想將外觀段落文本轉換爲錨鏈接。

$change = array(
    'google' => 'www.google.com', 
    'facebook' => 'www.facebook.com', 
); 

$text = " 
    <h1>Search on google for facebook</h1> 
    <p>Search on google for facebook</p> 
"; 

foreach ($change as $word => $url) { 
    $sentence = preg_replace('@(?<=\W|^)('.$word.')(?=\W|$)@i', '<a href="'.$url.'">$1</a>', $text); 
} 
echo $sentence; 

我想這個堅決：

<h1>Search on google for facebook</h1> 
<p>Search on <a href="www.google.com">google</a> for <a href="www.facebook.com">facebook</a></p> 

Answer 1

您可以嘗試先匹配p標籤和執行preg_replace_callback匿名函數內的所有替代：

$change = array(
    'google' => 'www.google.com', 
    'facebook' => 'www.facebook.com', 
); 

$text = " 
    <h1>Search on google for facebook</h1> 
    <p>Search on google for facebook</p> 
"; 

$sentence = preg_replace_callback('~(<p\b[^>]*>)(.*?)(</p>)~s', function($m) use ($change) { 
     return $m[1] . preg_replace(
       array_map(function ($x) { return '@(?<=\W|^)('.preg_quote($x, "@").')(?=\W|$)@i'; }, array_keys($change)), 
       array_map(function ($y) { return '<a href="'. $y .'">$1</a>'; }, array_values($change)), 
       $m[2]). $m[3]; } 
, $text); 

echo $sentence; 

見PHP demo。