在CodeIgniter中使用if語句的兩個插入查詢

我試圖通過檢查用戶類型在兩個表中添加信息。如果用戶是普通用戶，則必須在第一個表中輸入記錄，如果用戶類型是醫生，則必須在兩個表中輸入記錄。我工作在笨3.6在CodeIgniter中使用if語句的兩個插入查詢

public function model_signup() 
{ 
$nameVar    = $this->input->post("signup_name"); 
$emailVar   = $this->input->post("signup_email"); 
$phoneVar   = $this->input->post("signup_phone"); 
$passwordVar   = $this->input->post("signup_password"); 
$ifDoctorVar   = $this->input->post("signup_ifdoctor"); 
$pmdcVar    = $this->input->post("signup_pmdc"); 

$signu_query   = $this->db->query("SELECT * FROM `doc_users` WHERE `user_email`='".$emailVar."'"); 
if($signu_query->num_rows() >0){ 
return false; 
} 
else 
{ 

    $this->db->query("INSERT INTO `doc_users` 
    (`user_nicename`, 
    `user_login`, 
    `user_email`, 
    `display_name`, 
    `user_phone`, 
    `user_pass`, 
    `user_type`, 
    `user_registered`) 
    VALUES ('$nameVar', 
    '$emailVar', 
    '$emailVar', 
    '$nameVar', 
    '$phoneVar', 
    '$passwordVar', 
    '$ifDoctorVar', 
    NOW())"); 

    $user_id = $this->db->insert_id(); 

    if($ifDoctorVar=='Doctor') { // checking if user is doctor or not 

    $this->db->query("INSERT INTO `doc_doc_details` 
    (`ID`, 
    `pmdc_id`, 
    `email`, 
    `phone) 
    VALUES ('$user_id', 
    '$pmdcVar', 
    '$emailVar', 
    '$phoneVar')"); 
    return true; 
    } 

    } 
}

來源

2015-12-21 Kashif Latif

什麼錯誤你有？ – kc1994

得到2個錯誤，第一個是記錄沒有進入第二個表，第二個是提交後頁面重定向到錯誤頁面 –

當我試着用一個查詢一切工作正常 –

public function model_signup() 
{ 
$nameVar    = $this->input->post("signup_name"); 
$emailVar   = $this->input->post("signup_email"); 
$phoneVar   = $this->input->post("signup_phone"); 
$passwordVar   = $this->input->post("signup_password"); 
$ifDoctorVar   = $this->input->post("signup_ifdoctor"); 
$pmdcVar    = $this->input->post("signup_pmdc"); 

$signu_query   = $this->db->query("SELECT * FROM 
`doc_users`  WHERE `user_email`='".$emailVar."'"); 
if($signu_query->num_rows() >0){ 
return false; 
} 
else 
{ 

$this->db->query("INSERT INTO `doc_users` 
(`user_nicename`, 
`user_login`, 
`user_email`, 
`display_name`, 
`user_phone`, 
`user_pass`, 
`user_type`, 
`user_registered`) 
VALUES ('$nameVar', 
'$emailVar', 
'$emailVar', 
'$nameVar', 
'$phoneVar', 
'$passwordVar', 
'$ifDoctorVar', 
NOW())"); 

$user_id = $this->db->insert_id(); 

if($ifDoctorVar=='Doctor') { // checking if user is doctor or not 

$this->db->query("INSERT INTO `doc_doc_details` 
(`ID`, 
    `pmdc_id`, 
    `email`, 
    `phone) 
    VALUES ('$user_id', 
    '$pmdcVar', 
    '$emailVar', 
    '$phoneVar')"); 
    // return true remove this 
    } 

} 
}

來源

2015-12-22 04:51:55 kc1994

感謝您的解決方案 –

很高興幫助你... – kc1994

在CodeIgniter中使用if語句的兩個插入查詢

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