我是一個嘗試編寫網絡蜘蛛腳本的新手。 我想轉到一個頁面,在文本框中輸入數據,通過單擊提交按鈕轉到下一頁,並在新頁面上檢索所有數據,迭代。網絡爬蟲HTTP錯誤403:禁止
以下是代碼我想:
import urllib
import urllib2
import string
import sys
from BeautifulSoup import BeautifulSoup
hdr = {'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.64 Safari/537.11','Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8','Accept-Charset': 'ISO-8859-1,utf-8;q=0.7,*;q=0.3','Accept-Encoding': 'none','Accept-Language': 'en-US,en;q=0.8','Connection': 'keep-alive'}
values = {'query' : '5ed10c844ed4266a18d34e2ba06b381a' }
data = urllib.urlencode(values)
request = urllib2.Request("https://www.virustotal.com/#search", data, headers=hdr)
response = urllib2.urlopen(request)
the_page = response.read()
pool = BeautifulSoup(the_page)
print pool
以下是錯誤:
Traceback (most recent call last):
File "C:\Users\Dipanshu\Desktop\webscraping_demo.py", line 19, in <module>
response = urllib2.urlopen(request)
File "C:\Python27\lib\urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python27\lib\urllib2.py", line 406, in open
response = meth(req, response)
File "C:\Python27\lib\urllib2.py", line 519, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python27\lib\urllib2.py", line 444, in error
return self._call_chain(*args)
File "C:\Python27\lib\urllib2.py", line 378, in _call_chain
result = func(*args)
File "C:\Python27\lib\urllib2.py", line 527, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 403: Forbidden
我該如何解決這個問題?
錯誤的路徑。 'POST/search /' –
[urllib2.HTTPError:HTTP Error 403:Forbidden]可能的重複(https://stackoverflow.com/questions/13303449/urllib2-httperror-http-error-403-forbidden) – djinn