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我需要一些幫助。 所以我創建了一個通過cURL發送圖像數據的php腳本。 這裏是場景:將通過cURL接收的.tmp圖像轉換爲.jpeg
我已經上傳了一張圖片,然後我會通過cURL傳遞一個.jpeg文件擴展名的圖片。
在我的接收器上,我收到圖像,但圖像文件擴展名爲.tmp 在上傳它之前,我有辦法再次將它轉換爲.jpeg嗎?
這裏是我的代碼上傳遞的圖像:
$data = array(
"filename"=>$first_param,
"transno"=>$transno,
"type"=>$type,
"refno"=>$refno,
"custno"=>$custno,
"imei"=>$imei
);
$dataFields = http_build_query($data, '', '&');
$fields = array('uploaded_file' => '@' . $_FILES['uploaded_file']['tmp_name'], 'filename'=>$_FILES['uploaded_file']['name']);
$header = array('Content-Type: multipart/form-data');
$url = "http://url/directory/phpname.php?".$dataFields;
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_HTTPHEADER, $header);
curl_setopt($ch, CURLOPT_INFILESIZE, $_FILES['uploaded_file']['size']);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $fields);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
$result = curl_exec($ch);
curl_close($ch);
現在,這裏是我的代碼爲接受它:
$filename = $_GET['filename'];
$transno = $_GET['transno'];
$type = $_GET['type'];
$refno = $_GET['refno'];
$custno = $_GET['custno'];
$remarks="";
$imei = $_GET['imei'];
$upload = new Upload();
$upload->Upload($filename, $transno, $type, $refno, $custno, $remarks, $imei, $_FILES);
接收到的圖像將是$ _FILES。 謝謝