2017-02-18 195 views
0

我有兩個實體類。用戶和FriendStatus.Friend狀態保存有關來自其他用戶的朋友請求的數據。hibernate @onetomany雙向映射不能正確映射數據

用戶:

@Entity 
@Table(name = "USERS") 
@XmlRootElement 
public class User implements Serializable { 

@OneToMany(cascade = CascadeType.ALL, mappedBy = "acceptor") 
@LazyCollection(LazyCollectionOption.FALSE) 
private List<Message> acceptedMessages; 

@OneToMany(cascade = CascadeType.ALL, mappedBy = "sender") 
@LazyCollection(LazyCollectionOption.FALSE) 
private List<Message> sentMessages; 

@Id 
@GeneratedValue(strategy = GenerationType.IDENTITY) 
private Long id; 
private String username; 
private String password; 

@Column(name = "phone_number") 
private String phoneNumber; 

@OneToMany(cascade = CascadeType.ALL) 
@LazyCollection(LazyCollectionOption.FALSE) 
private List<User> friends; 

@OneToMany(cascade = CascadeType.ALL,mappedBy="requestAcceptor") 
@LazyCollection(LazyCollectionOption.FALSE) 
@JsonIgnoreProperties("requestAcceptor") 
private List<FriendStatus> acceptedFriendRequests; 

@OneToMany(cascade = CascadeType.ALL,mappedBy = "requestSender") 
@LazyCollection(LazyCollectionOption.FALSE) 
@JsonIgnoreProperties("requestSender") 
private List<FriendStatus> sentFriendRequests; 

@Column(name = "profile_status") 
private String profileStatus; 

@Enumerated(EnumType.STRING) 
@Column(name = "activation_status") 
private UserActivationStatus activationStatus; 

FriendStatus:

@Entity 
@Table(name="FRIEND_STATUS") 
public class FriendStatus implements Serializable { 

@Id 
@GeneratedValue(strategy = GenerationType.IDENTITY) 
private long Id; 

@ManyToOne(cascade = CascadeType.ALL) 
@JoinColumn(name="request_sender_id") 
@JsonIgnoreProperties("sentFriendRequests") 
private User requestSender; 

@ManyToOne(cascade = CascadeType.ALL) 
@JoinColumn(name="request_acceptor_id") 
@JsonIgnoreProperties("acceptedFriendRequests") 
private User requestAcceptor; 

@Enumerated(EnumType.STRING) 
@Column(name = "request_status") 
private FriendRequestStatus friendRequestStatus; 

當我第一次節省FriendStatus目的是它的工作原理fine.But當我保存的對象的第二時間以相同requestAcceptor對象的數據庫,休眠從request_acceptor_id列刪除先前的id並將其寫入新行。請幫助我。

編輯:

這是我將我的對象保存到數據庫的方法。

public T create(T object) { 
T objectFromDB = object; 
Session session = NewHibernateUtil.getSessionFactory().openSession(); 
Transaction transaction = null; 
try { 
    transaction = (Transaction) session.beginTransaction(); 
    session.save(object);   
    transaction.commit(); 

} catch (HibernateException e) { 
     if (session != null){ 
       session.getTransaction().rollback(); 
      } 
    e.printStackTrace(); 
} finally { 
    session.close(); 
} 
return objectFromDB; 
} 

這是我調用創建方法的方法:

public void sendFriendRequest(FriendStatus object) { 
    FriendStatus status = fDao.create(object);//fDao is the object from Dao class which includes create method. 
} 

這是我的控制器:

@RequestMapping(value="/sendFriendRequest",method = RequestMethod.POST,consumes = MediaType.APPLICATION_JSON,produces = MediaType.APPLICATION_JSON) 
public String sendFriendRequest(@RequestBody FriendStatus status) { 
    serviceUser.sendFriendRequest(status);//serviceUser is the object from class that includes sendFriendRequest method. 
    return "OK"; 
} 

這是我在db表:

+====+================+=====================+===================+ 
| id | request_status | request_acceptor_id | request_sender_id | 
+====+================+=====================+===================+ 
| 18 | WAITING  | NULL    |    29 | 
+----+----------------+---------------------+-------------------+ 
| 19 | WAITING  | 23     |    30 | 
+----+----------------+---------------------+-------------------+ 

當我保存FriendStatus對象(它來自fr om客戶端)與requestSender其中ID爲29和requestAcceptor對象的ID爲23 Hibernate將其保存到ID爲18的列。之後,當我保存第二個FriendStatus對象與requestSender其中ID爲30和requestAcceptor對象的ID爲23,休眠將id爲18的行中的NULL替換爲request_acceptor_id,然後在db中創建新的行,其中request_acceptor_id是23.But我希望當我添加第二個對象時,第一個對象不會改變。我不想用request_acceptor_id替換NULL當我創建新的列與相同的request_acceptor_id。

+0

安置自己的代碼中刪除級聯規則,並明確說明您認爲是什麼做的,它做什麼代替。 –

+0

我編輯的問題。請說如果我應該添加一些東西。 –

+0

我已經說過了:發佈你的代碼,並清楚地解釋你期望它做什麼,以及它做了什麼。 –

回答

0

它與你的級聯設置,

嘗試使用以下保存:

public void sendFriendRequest(FriendStatus status) { 

    User requester=userDao.findOne(status.getRequestAcceptor.getId()); 
    User sender=userDao.findOne(status.getRequestSender.getId()); 
    ...... 
    statusDao.create(status); 
    status.getRequestAcceptor(requester); 
    status.getRequestSender(sender); 
    statusDao.update(status); 

} 

用戶的這一地位被攜帶有私人列表sentFriendRequests和私有列表acceptedFriendRequests;設置爲空列表

Ofcause它的作品了,甚至更好,如果你的交易是整體功能之外,那麼你可以使用: sender.getSentFriendRequests()加(狀態)和reqester.getacceptedFriendRequests()加(狀態)。我的猜測是@OneToMany點,Cascade.All

否則你就剛剛從集合

+0

fantactic !!!有效 !!非常感謝你 –