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我正在閱讀Wrox的書「Beginning PHP，Apache，MySQL web development」。我一直在逐字追蹤，出於某種原因，我對代碼存在問題。編輯說我的代碼沒有錯誤。但是當我運行它時，會給我以下消息： 「您的SQL語法有錯誤;請檢查與您的MySQL服務器版本相對應的手冊，以找到在'第3行'附近使用的正確語法」，這裏是以下代碼問題與heredoc和PHP
<?php
//take in the id of a director and return his/her full name
function get_director() {
global $db;
$query = 'SELECT people_fullname
FROM people
WHERE people_id = ' . $director_id;
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $people_fullname;
}
//take in the id of a lead actor and return his/her full name
function get_leadactor($leadactor_id) {
global $db;
$query = 'SELECT people_fullname
FROM people
WHERE people_id = ' . $leadactor_id;
$result = mysql_query($query, $db) or die (mysql_error($db));
$extract($row);
return $people_fullname;
}
// take in the id of a movie type
// and return the meaningful textual description
function get_movietype($type_id) {
global $db;
$query = 'SELECT movietype_label
FROM movietype
WHERE movietype_id = ' . $type_id;
$result = mysql_query($query, $db) or die (mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $movietype_label;
}
// conect to MySQL
$db = mysql_connect('localhost', 'root', 'root') or
die ('unable to connect. Check your parameters');
// make sure you are yousing the right database
mysql_select_db('moviesite', $db) or die(mysql_error($db));
// retrieve information
$query = 'SELECT movie_name, movie_year, movie_director, movie_leadactor, movie_type
FROM movie
ORDER BY movie_name ASC, movie_year DESC';
$result = mysql_query($query, $db) or die ($mysql_error($db));
// determine number of rows in returned result
$num_movies = mysql_num_rows($result);
$table = <<<ENDHTML
<div style ="text-align: center;">
<h2>Movie Review Database</h2>
<table border="1" cellpadding="2" cellspacing="2" style="width: 70%; margin-left: auto; margin-right:auto;">
<tr>
<th>Movie Title</th>
<th>Year of the release</th>
<th>Movie Director</th>
<th>Movie Lead Actor</th>
<th>Movie Type</th>
</tr>
ENDHTML;
//loop throught the results
while ($row = mysql_fetch_assoc($result)) {
extract($row);
$director = get_director($movie_director);
$leadactor = get_leadactor($movie_leadactor);
$movietype = get_movietype($movie_type);
$table .= <<<ENDHTML
<tr>
<td>$movie_name</td>
<td>$movie_year</td>
<td>$director</td>
<td>$leadactor</td>
<td>$movietype</td>
</tr>
ENDHTML;
}
$table .= <<<ENDHTML
</table>
<p>$num_movies Movies</p>
</div>
ENDHTML;
echo $table
?>
之後，我試圖複製和粘貼確切的代碼想也許我做錯了什麼 在這裏它下面的代碼：
<?php
// take in the id of a director and return his/her full name
function get_director($director_id) {
global $db;
$query = 'SELECT
people_fullname
FROM people
WHERE
people_id = ' . $director_id;
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $people_fullname;
}
// take in the id of a lead actor and return his/her full name
function get_leadactor($leadactor_id) {
global $db;
$query = 'SELECT
FROM
people WHERE
people_id = ' . $leadactor_id;
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $people_fullname;
}
// take in the id of a movie type and return the meaningful textual
// description
function get_movietype($type_id) {
global $db;
$query = 'SELECT
movietype_label
FROM
movietype
WHERE
movietype_id = ' . $type_id;
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $movietype_label;
}
//connect to MySQL
$db = mysql_connect('localhost', 'root', 'root') or
die ('Unable to connect. Check your connection parameters.');
// make sure you’re using the right database
mysql_select_db('moviesite', $db) or die(mysql_error($db));
// retrieve information
$query = 'SELECT
movie_name, movie_year, movie_director, movie_leadactor,
movie_type
FROM
movie
ORDER BY
movie_name ASC,
movie_year DESC';
$result = mysql_query($query, $db) or die(mysql_error($db));
// determine number of rows in returned result
$num_movies = mysql_num_rows($result);
$table = <<<ENDHTML
<div style="text-align: center;">
<h2>Movie Review Database</h2>
<table border="1" cellpadding="2" cellspacing="2"
style="width: 70%; margin-left: auto; margin-right: auto;">
<tr>
<th>Movie Title</th>
<th>Year of Release</th>
<th>Movie Director</th>
<th>Movie Lead Actor</th>
<th>Movie Type</th>
</tr>
ENDHTML;
// loop through the results
while ($row = mysql_fetch_assoc($result)) {
extract($row);
$director = get_director($movie_director);
$leadactor = get_leadactor($movie_leadactor);
$movietype = get_movietype($movie_type);
$table .= <<<ENDHTML
<tr>
<td>$movie_name</td>
<td>$movie_year</td>
<td>$director</td>
<td>$leadactor</td>
<td>$movietype</td>
</tr>
ENDHTML;
}
$table .= <<<ENDHTML
</table>
<p>$num_movies Movies</p>
</div>
ENDHTML;
echo $table;
?>
，當我跑的代碼此時，表頭顯示但部分代碼也顯示在瀏覽器上。它看起來像這樣： ENDHTML; //循環結果while（= mysql_fetch_assoc（Resource id＃3））{extract（）; = get_director（）; = get_leadactor（）; = get_movietype（）; 。= < < ENDHTML; } = < <
任何幫助將不勝感激我的新節目感謝
請，或不使用'mysql_ *'功能（HTTP：/ /stackoverflow.com/questions/12859942/why-shouldnt-i-use-mysql-functions-in-php），他們不再維護，並[正式棄用]（https://wiki.php.net/rfc/ mysql_deprecation）。學習[準備的語句]（http://en.wikipedia.org/wiki/Prepared_statement），並使用[PDO]（http://us1.php.net/pdo）或[MySQLi]（http：// us1.php.net/mysqli）。您還將希望[防止SQL注入！]（http://stackoverflow.com/questions/60174/how-can-i-prevent-sql-injection-in-php） – 2014-11-24 15:53:45
您不能有任何空格或製表符之前關閉heredoc的標識符。而且你應該只加入一個查詢來加入必要的表格，不要查詢循環中的其他信息。 – jeroen 2014-11-24 15:54:54
迴應你的'$ query'，你會發現它的問題。這些行上的報價問題很可能是'WHERE people_id ='。 $ DIRECTOR_ID;'。 – 2014-11-24 15:54:58