使用printf並遞增地增加一個字符串變量？

Question

我想輸出一個字符串，但我需要在字符串前增加一個數字，直到它結束。我正在從txt文件中提取數據。

/Circle/{n=split($2,array,",") 
if (index(array[2],"x")){x=array[3]} 
else if (index(array[2],"y")){y=array[3]} 
else if (index(array[2],"z")){z=array[3]} 
else if (index(array[2],"r")){z=array[3]} 
else { printf("CIRCLE/%.4f,%.4f,%.4f,%.4f\n", x, y, r, z) }} 

這是我現在和它的輸出是這樣

CIRCLE/0.0000,0.0000,0.0000,1.0068

CIRCLE/10.0000,0.0000,0.0000,1.9068

CIRCLE /5.0000,0.0000,0.0000,1.8068

我需要它看起來像這樣

CR1 = CIRCLE/0.0000,0.0000,0.0000,1.0068

CR2 = CIRCLE/10.0000,0.0000,0.0000,1.9068

CR3 = CIRCLE/5.0000,0.0000,0.0000,1.8068

Answer 1

您的printf改爲：

printf("%sCIRCLE/%.4f,%.4f,%.4f,%.4f\n", "CR" ++i "=", x, y, r, z) 

（此外，這是稍微更地道，不使用與打印語句括號）：

printf "%sCIRCLE/%.4f,%.4f,%.4f,%.4f\n", "CR" ++i "=", x, y, r, z 

Answer 2

你沒有張貼任何樣品輸入，所以這顯然是未經測試，但你的代碼也許應該是這樣的：

/Circle/ { 
    split($2,array,/,/) 
    if (array[2] ~ /[xyzr]/) { 
     v[array[2]] = array[3] 
    } 
    else { 
     printf "CR%d=CIRCLE/%.4f,%.4f,%.4f,%.4f\n", ++cnt, v["x"], v["y"], v["r"], v["z"] 
    } 
}