SearchView AsyncTask UI未正確更新

我在實現searchview時顯示其服務器數據結果時遇到問題。我目前使用一個AsyncTask，所以我不會阻止用戶界面。這裏是我是如何實現它：SearchView AsyncTask UI未正確更新

searchView.setOnQueryTextListener(new OnQueryTextListener() { 

    @Override 
    public boolean onQueryTextChange(String query) { 

     if (query.length() > 0) { 
      new GetSearchByNameResultTask(searchView).execute(query); 
     } else { 
      return false; 
     } 

     return true; 
    } 

    @Override 
    public boolean onQueryTextSubmit(String arg0) { 
     // TODO Auto-generated method stub 
     return false; 
    } 

});

GetSearchByNameResultTask

class GetSearchByNameResultTask extends AsyncTask<String, Void, String> { 

    private SearchView searchView; 

    public GetSearchByNameResultTask(SearchView searchView) { 
     this.searchView = searchView; 
    } 

    @Override 
    protected String doInBackground(String... params) { 
     // TODO Auto-generated method stub 
     return WebRequestHelper.getInfo(params[0]); 
    } 

    @Override 
    protected void onPostExecute(String result) { 
     // TODO Auto-generated method stub 
     super.onPostExecute(result); 
     AppLog.d(TAG, "Result search: " + result); 
     Gson gson = new Gson(); 

     searchResponseList = gson.fromJson(result, new TypeToken<List<Info>>() { 
     }.getType()); 

     loadHistory(searchView, searchResponseList); 
     // TODO: search adapter 
    } 
}

loadHistory（）代碼：

private void loadHistory(SearchView searchView, List<AppInfo> searchResponse) { 

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB) { 
     searchView.setSuggestionsAdapter(null); 
     // Cursor 
     String[] columns = new String[] { "_id", "text" }; 
     Object[] temp = new Object[] { 0, "default" }; 

     MatrixCursor cursor = new MatrixCursor(columns); 

     final List<Info> items = searchResponse; 

     for (int i = 0; i < items.size(); i++) { 

      temp[0] = i; 
      temp[1] = items.get(i).getName(); 
      cursor.addRow(temp); 
     } 
     CursorAdapter ca = new AppListSearchAdapter(this, cursor, items); 
     new AsyncQueryResult(cursor,ca).executeOnExecutor(AsyncTask.SERIAL_EXECUTOR); 
     // SearchView 
     searchView.refreshDrawableState(); 
     searchView.setSuggestionsAdapter(ca); 
     searchView.setOnSuggestionListener(new OnSuggestionListener() { 

      @Override 
      public boolean onSuggestionSelect(int position) { 
       // TODO Auto-generated method stub 
       return false; 
      } 

     }); 
    } 
}

問題一切運行正常的。我收到搜索結果。但我在更新視圖時遇到問題。用一個例子也許最好的解釋：

數據：在搜索

 
Hell 
Hello 
Helicopter

文本：赫爾

結果：地獄

：在搜索

 
Hello World 
Hello 
Helicopter

文本

 
Hell 
Hello 
[extra empty space]

額外的空白空間是我的問題。「列表視圖」不會更新以適應結果，直到我輸入'你好'

來源

2014-09-29 hadez30

我忘了回答這個問題。

我試圖解決這個問題，雖然這對我來說有點破綻。這是我做的：

@Override 
public void onLoadFinished(Loader<Cursor> cursorLoader, Cursor cursor) { 
    searchAdapter = new SearchAdapter(this, cursor, false); 

    mSearchView.setSuggestionsAdapter(searchAdapter); 

    new Handler().postDelayed(new Runnable() { 
     @Override 
     public void run() { 
      searchAdapter.notifyDataSetChanged(); 
     } 
    }, 200); 

    //Reload fragment to show list 
}

這將強制刷新搜索視圖的適配器。新的Handler（）。postDelayed（）是這裏的關鍵。

希望這個解決方案有幫助。

來源

2015-03-12 16:51:52 hadez30

SearchView AsyncTask UI未正確更新

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