2014-10-31 160 views
0

因此,在我的模型中,我有一個特定的配置文件,與具有與django用戶模型的一對一關係的更一般的配置文件具有一對一的關係。我希望能夠在django管理員中填寫一個表單,並創建所有三個模型的實例,並建立關係。自定義管理員創建表單

我還沒有搞亂django管理員太多,所以我不完全知道如何使它工作。這裏是我的失敗嘗試:

class CreateSpecializedProfileAdminForm(forms.ModelForm): 

    class Meta: 
     exclude = ['profile'] 

    first_name = forms.CharField(max_length=30) 
    last_name = forms.CharField(max_length=30) 
    email = forms.EmailField(max_length=30) 
    password = forms.CharField(max_length=30) 
    confirm_password = forms.CharField(max_length=30) 

    def clean(self): 
     password = self.cleaned_data['password'] 
     confirm_password = self.cleaned_data['confirm_password'] 
     if len(self.cleaned_data['password']) < 6: 
      raise forms.ValidationError('Password must be at least 6 characters.') 
     if password != confirm_password: 
      raise forms.ValidationError('Passwords must match.') 
     return super(CreateSpecializedProfileAdminForm, self).clean() 

    def save(self, commit=True): 
     from django.contrib.auth.models import User 
     first = self.cleaned_data['first_name'] 
     last = self.cleaned_data['last_name'] 
     email = self.cleaned_data['email'] 
     password = self.cleaned_data['password'] 
     user = User.objects.create_user(email, email, password) 
     user.first_name = first 
     user.last_name = last 
     user.save() 
     profile = UserProfile() 
     profile.user_auth = user 
     profile.save() 
     specialized_profile = SpecializedProfile() 
     specialized_profile.profile = profile 
     specialized_profile.save() 
     return specialized_profile 

class SpecializedProfileAdmin(admin.ModelAdmin): 

form = CreateSpecializedProfileAdminForm 

admin.site.register(SpecializedProfile, SpecializedProfileAdmin) 

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