所以管理員有選擇,他選擇要導出通過選擇我存儲在山坳[] ... 這裏是我的代碼爲出口導出數據從SQL到使用Excel PHP
session_start();
$HOST = 'localhost';
$USERNAME = 'root';
$PASSWORD = '';
$DB = 'fyp_db';
$link = mysqli_connect($HOST, $USERNAME, $PASSWORD, $DB);
if (is_array($_POST['col'])) {
$sql = "SELECT ";
foreach ($_POST['col'] AS $value) {
$sql .= "{$value}, ";
}
$sql = substr($sql, 0, -2);
$sql .= " FROM account, coursedetail, coursecategory";
/*echo "sql= " . $sql . "<br /><br />\n";*/
} else {
echo "No column was selected<br /><br />\n";
}
function cleanData(&$str) { $str = preg_replace("/\t/", "\\t", $str); $str = preg_replace("/\r?\n/", "\\n", $str); if(strstr($str, '"')) $str = '"' . str_replace('"', '""', $str) . '"'; }
$filename = "website_data.xls";
header("Content-Type: text/plain");
$flag = false;
$result = mysqli_query($link, $sql) or die(mysqli_error($link));
while(false !== ($row = mysql_fetch_assoc($result))) {
if(!$flag) {
// display field/column names as first row
echo implode("\t", array_keys($row)) . "\r\n";
$flag = true;
}
array_walk($row, 'cleanData');
echo implode("\t", array_values($row)) . "\r\n";
}
複選框擅長什麼
我的錯誤..
警告:mysql_fetch_assoc()預計參數1是資源,對象C中給出:\ XAMPP \ htdocs中\項目\ export_successful.php上線
爲什麼? :(
也許你的SQL是無效的。請發表你的SQL查詢與echo()。 也你不使用mysql_real_escape_string()或類似的東西! – ComFreek
當我回聲$ sql;我看到這個SQL = SELECT名稱,聯繫人號碼,地址,date_of_birth,電子郵件,標題,類別FROM account,coursedetail,coursecategory – user861896
SQL是有效的,但我認爲問題是mysql和mysqli正如Marc B所說的。 – ComFreek