AJAX請求提交，但不接收POST值

Question

我正在處理某些事情，並且我有一個非常奇怪的問題。我提出一個AJAX請求像以下：

x = new XMLHttpRequest(); 
x.open('POST', url, true); 
x.setRequestHeader('Content-type', 'application/x-www-form-urlencoded'); 
x.onload = function(){ 
    console.log(x.responseText); 
}; 
x.send(data); 

的問題是，當我提交請求時，PHP沒有收到POST值。該data變量看起來像以下：

Object { wordtype: "noun", word: "computer" } 

而且PHP像以下：

if(!isset($_POST['wordtype']) || !isset($_POST['word'])){ 
    echo "error 1"; 
    exit; 
} else { 
    $wordlist = json_decode(file_get_contents("words.json"), true); 
    $wordlist[$_POST['word']] = $_POST['wordtype']; 
    file_put_contents("words.json", json_encode($wordlist)); 
    echo "success"; 
} 

的x.responseText值總是error 1;

謝謝
雅克·瑪萊

Answer 1

這個例子的工作原理：

var http = new XMLHttpRequest(); 
var url = "ajax.php"; 
var params = "wordtype=noun&word=computer"; 
http.open("POST", url, true); 

//Send the proper header information along with the request 
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); 
http.setRequestHeader("Content-length", params.length); 
http.setRequestHeader("Connection", "close"); 

http.onreadystatechange = function() {//Call a function when the state changes. 
    if(http.readyState == 4 && http.status == 200) { 
     alert(http.responseText); 
    } 
} 
http.send(params);