卡在while循環

Question

我想爲我的侄子做一個骰子tosser，所以他可以玩沒有骰子的棋盤遊戲。即使我輸入了一個真實的條件，我也陷入了一個while循環。我試圖讓他選擇他想用的骰子，但是如果他選擇了一個錯誤的骰子，那麼它會要求他再次輸入。我的代碼是...

dice_select = input('Enter the amount of sides are on the dice you want to throw, either 4, 6, or 12: ') 
while dice_select != 4 or dice_select != 6 or dice_select != 12: 
    dice_select = int(input('Sorry thats not quite right. Enter the amount of sides are on the dice you want to throw, either 4, 6, or 12: ')) 

如果我輸入4,6或12，那麼當它應該繼續時，它仍然使我進入循環。

Answer 1

試試這個：

dice_select = int(input('Enter the amount of sides are on the dice you want to throw, either 4, 6, or 12: ')) 
    while not (dice_select == 4 or dice_select == 6 or dice_select == 12): 
     dice_select = int(input('Sorry thats not quite right. Enter the amount of sides are on the dice you want to throw, either 4, 6, or 12: ')) 

這意味着循環，直到dice_select等於4,6或12

隨着你的計劃，你的while循環的條件永遠是正確的，因爲當它等於4，你的程序正在檢查錯誤或真實或真實，這將永遠是真實的。

換句話說，您的程序正在尋找何時dice_select等於4,6和12的時間。這是不可能的。