如何分割和存儲只在python中的一些值？

-1

Breathing 1:-29.9396 9:-32.0895 13:-35.6787 2:-36.8527 17:-37.3622 8:-38.0584 14:-38.5265 18:-38.7567 16:-38.7663 12:-39.1036 7:-39.5838 4:-40.653 15:-41.2627 3:-42.5983 5:-43.5966 10:-48.5747 11:-48.8823 6:-241.384 
Breathing 1:-30.3629 9:-30.9582 17:-34.2767 13:-34.2944 14:-35.9349 16:-36.4528 2:-36.5194 18:-37.2092 8:-37.425 12:-37.5344 15:-38.001 3:-38.4113 7:-38.8753 5:-40.2013 4:-42.5538 10:-43.9502 11:-44.9487 6:-227.162 
Breathing 1:-30.3253 9:-36.9927 8:-38.0383 4:-39.9291 13:-40.0669 2:-40.3448 18:-40.8734 14:-40.8901 16:-41.7204 12:-42.6082 7:-43.1386 17:-44.0876 3:-48.8257 15:-48.8814 5:-51.2907 11:-58.4311 10:-59.1803 6:-266.998 
Breathing 15:-35.338 9:-35.8658 17:-38.6632 12:-39.154 13:-40.9085 3:-42.836 1:-43.3277 11:-43.684 2:-43.8531 8:-45.7809 18:-46.9128 16:-47.028 14:-47.6292 5:-49.7012 7:-49.8664 4:-61.5319 10:-93.743 6:-215.678 
Breathing 18:-27.0995 14:-29.5464 1:-30.6396 9:-30.9543 13:-33.1009

我如何:-後的值存儲在一個數組中的元素？

我知道這個代碼：

for line in lines: 
    items = line.split()[1:] 
    items = [item.split(':')[0] for item in items] 
    items = map(int,items) 
    rows.append(items)

店:以前生產的。

來源

2012-06-14 Aiurea Adica tot YO

它是'： - '符號還是它只是一個負數？ – Ribtoks

你爲什麼使用'map'？你也應該使用列表理解來應用'int'。 – ecatmur

如果

items = [item.split(':')[0] for item in items]

店:前的值，然後

items = [item.split(':')[1] for item in items]

存儲值:後。

來源

2012-06-14 09:58:37 ecatmur

在第三行改變[0]改爲[1]。這將從溢出而不是第一個獲得第二個元素。

此外，由於第二個數字不是整數，因此map(int, items)將失敗。您可能想要使用float。這裏是你可以作爲測試

#!/usr/bin/env python 
lines = """Breathing 1:-29.9396 9:-32.0895 13:-35.6787 2:-36.8527 17:-37.3622 8:-38.0584 14:-38.5265 18:-38.7567 16:-38.7663 12:-39.10 
Breathing 1:-30.3629 9:-30.9582 17:-34.2767 13:-34.2944 14:-35.9349 16:-36.4528 2:-36.5194 18:-37.2092 8:-37.425 12:-37.5344 15:-38.00 
Breathing 1:-30.3253 9:-36.9927 8:-38.0383 4:-39.9291 13:-40.0669 2:-40.3448 18:-40.8734 14:-40.8901 16:-41.7204 12:-42.6082 7:-43.138 
Breathing 15:-35.338 9:-35.8658 17:-38.6632 12:-39.154 13:-40.9085 3:-42.836 1:-43.3277 11:-43.684 2:-43.8531 8:-45.7809 18:-46.9128 1 
Breathing 18:-27.0995 14:-29.5464 1:-30.6396 9:-30.9543 13:-33.1009""".split('\n') 

rows = [] 

for line in lines: 
    items = line.split()[1:] 
    items = [item.split(':')[1] for item in items] 
    items = map(float,items) 
    rows.append(items) 

from pprint import pprint 
pprint(rows)

來源

2012-06-14 09:58:46 rjmunro

我覺得後續的問題是爲什麼它將數字截斷爲整數... – mensi

@rjmunro謝謝....我想你可能會這樣，但不想毀了東西:)。 –

@mensi它將它們截斷爲int，以便它們可以添加到其他地方。 –

>>> import re 
>>> rows = [] 
>>> for line in s.split('\n'): 
    for item in line.split(): 
     m = re.match(r'\d+:-([\d\.]+)', item) 
     if m: 
      rows.append(m.groups()[0]) 


>>> rows 
['29.9396', '32.0895', '35.6787', '36.8527', '37.3622', '38.0584', '38.5265', '38.7567', '38.7663', '39.1036', '39.5838', '40.653', '41.2627', '42.5983', '43.5966', '48.5747', '48.8823', '241.384', '30.3629', '30.9582', '34.2767', '34.2944', '35.9349', '36.4528', '36.5194', '37.2092', '37.425', '37.5344', '38.001', '38.4113', '38.8753', '40.2013', '42.5538', '43.9502', '44.9487', '227.162', '30.3253', '36.9927', '38.0383', '39.9291', '40.0669', '40.3448', '40.8734', '40.8901', '41.7204', '42.6082', '43.1386', '44.0876', '48.8257', '48.8814', '51.2907', '58.4311', '59.1803', '266.998', '35.338', '35.8658', '38.6632', '39.154', '40.9085', '42.836', '43.3277', '43.684', '43.8531', '45.7809', '46.9128', '47.028', '47.6292', '49.7012', '49.8664', '61.5319', '93.743', '215.678', '27.0995', '29.5464', '30.6396', '30.9543', '33.1009'] 
>>>

來源

2012-06-14 10:14:08 Emmanuel

使用re模塊運行一個完整的Python腳本！

import re 
import numpy as np 

fobj=open.("yourFile", "r") 
data=fobj.read() 
fobj.close() 

r=re.findall(r":-[0-9]{1,3}.[0-9]{1,5}", data) 
for i in xrange(len(r)): 
    r[i]=r[i].lstrip(":") 
array=np.array(r).astype(float)

如果所有的值是負的，你可以通過刪除既簡化了代碼，在re.findall聲明:及以下for循環。輸出：

array([ -29.9396, -32.0895, -35.6787, -36.8527, -37.3622, -38.0584, 
    -38.5265, -38.7567, -38.7663, -39.1036, -39.5838, -40.653 , 
    -41.2627, -42.5983, -43.5966, -48.5747, -48.8823, -241.384 , 
    -30.3629, -30.9582, -34.2767, -34.2944, -35.9349, -36.4528, 
    -36.5194, -37.2092, -37.425 , -37.5344, -38.001 , -38.4113, 
    -38.8753, -40.2013, -42.5538, -43.9502, -44.9487, -227.162 , 
    -30.3253, -36.9927, -38.0383, -39.9291, -40.0669, -40.3448, 
    -40.8734, -40.8901, -41.7204, -42.6082, -43.1386, -44.0876, 
    -48.8257, -48.8814, -51.2907, -58.4311, -59.1803, -266.998 , 
    -35.338 , -35.8658, -38.6632, -39.154 , -40.9085, -42.836 , 
    -43.3277, -43.684 , -43.8531, -45.7809, -46.9128, -47.028 , 
    -47.6292, -49.7012, -49.8664, -61.5319, -93.743 , -215.678 , 
    -27.0995, -29.5464, -30.6396, -30.9543, -33.1009])

來源

2012-06-14 11:17:59 MaxPowers

模式'[0-9]'可以替換爲'\ d'：恕我直言，它簡化了可讀性。 – Emmanuel

如何分割和存儲只在python中的一些值？

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