SQL總和查詢問題

Question

我是SQL Server的新手，併爲此苦苦掙扎。

我有兩個選擇語句

SELECT 
    SUM(Amount) AS "MONDAY" 
FROM 
    Transaction 
WHERE 
    Transaction_Date = '2015-12-21 00:00:00.000' 

SELECT 
    SUM(Amount) AS "TUESDAY" 
FROM 
    Transaction 
WHERE 
    Transaction_Date = '2015-12-22 00:00:00.000' 

他們的結果是2,00,000和3,00,000分別

我想要的輸出被示爲兩列

（柱1 +週一）和（列2 =星期二）在SQL Server屏幕上

Answer 1

一個選項是使用conditional aggregation爲：

SELECT SUM(CASE WHEN Transaction_Date = '2015-12-21 00:00:00.000' 
      THEN Amount END) AS "MONDAY" , 
     SUM(CASE WHEN Transaction_Date = '2015-12-22 00:00:00.000' 
      THEN Amount END) AS "TUESDAY" 
FROM Transaction 

Answer 2

select datepart(dw, transactiondate), 
    sum(amount) [sum] 
from transaction 
where transaction_date between '2015-12-22' and '2015-12-23' 
group by datepart(dayofweek, transactiondate) 

記住，這是僞代碼，我找了「星期幾」的屬性...

查找日期部分在這裏：https://msdn.microsoft.com/en-us/library/ms174420.aspx

Answer 3

我認爲你需要使用MSSQL Pivot函數將行轉換爲列。 檢查這個問題。也許這可以幫助你： Convert Rows to columns using 'Pivot' in SQL Server