php上傳圖像和顯示數據庫（錯誤）

我想上傳一個圖像並顯示它與數據庫我設法使它上傳和連接到數據庫，但它不顯示它有人可以採取看我在告訴我什麼代碼我做錯了：php上傳圖像和顯示數據庫（錯誤）

的db.php中：

<?php 
$host = "localhost"; 
$username = "root"; 
$password = ""; 
$db_name = "db_php_school"; 

    mysql_connect($host,$username,$password) or die("Database not connect"); 
mysql_select_db($db_name) or die ("could not connect databse"); 
error_reporting("E_ERROR_WORKING"); 
echo "Database connecet success"; 


?>

這是在index.php：

<?php 


include './classes/image_class.php'; 

$obj_image = new Image(); 

if(@$_POST['Submit']) 
{ 
$obj_image->image_name=str_replace("'", "''", $_POST['txt_image_name']); 
$obj_image->image=str_replace("'", "''", $_POST['txt_image']); 

    $obj_image->Insert_into_image(); 

    $data_image=$obj_image->get_all_image_list(); 
$row=mysql_num_rows($data_image); 
} 

?> 

<!DOCTYPE html> 
<html> 
<head> 
<title>NOvaeye </title> 
</head> 
<body> 
<CENTER><H1>Novaeyewear</H1></CENTER> 
<CENTER><H2>Sunglass</H2></CENTER> 

    <CENTER> 
    <form method="post" enctype="multipart/form-data"> 
    <table border="1" width="80%"> 
    <tr> 
    <th width="50%">Image NAme</th> 
    <td width="50%"><input type="text" name="txt_image_name"></input></td> 
    </tr> 
    <tr> 
    <th width="50%">Upload IMage</th> 
    <td width="50%"><input type="file" name="txt_image"></input></td> 
    </tr> 
    <tr> 
    <td></td> 
    <td width="50%"><input type="submit" name="Submit" value="Submit"></input></td> 
    </tr> 
    </table> 
    </form> 
</CENTER> 

    <?php 
    if($row!=0) 
    { 
    ?> 
    <center> 
    <table width="80%" border="1"> 
    <?php 
    $icount = 1; 
    while($data= mysql_fetch_assoc($data_image)) 
    { 
    ?> 
    <tr> 
     <td style="text-align:center" style="width:10%;"><?php echo $icount; ?></td> 
     <td style="text-align:center" style="width:20%;"><?php echo $data['image_name']?></td> 
     <td style="text-align:center" style="width:50%;><img src="images/<?php echo $data['image']; ?>" width="400px" height="200px"></td> 
    </tr> 
    <?php 
    $icount++; 
    } 
    ?> 
    </table> 
    </center> 
    <?php 
} 

    ?> 
</body> 
</html>

這就是image_class.php

<?php 
include 'db/db.php' ; 

    class Image{ 

    var 
    $image_id, 
    $image_name, 
    $image; 

    function Insert_into_image(){ 
    if(isset($_FILES['txt_image'])) 
    { 
     $tempname = $_FILES['txt_image']['tmp_name']; 
     $originalname =$_FILES['txt_image']['name']; 
     $size =($_FILES['txt_image']['size']/5242888). "MB<br>"; 
     $type=$_FILES['txt_image']['type']; 
     $image=$_FILES['txt_image']['name']; 
     move_uploaded_file($_FILES['txt_image']['tmp_name'],"images/".$_FILES['txt_image']['name']); 
     } 


    $query = "Insert into t_image_upload 
    (
    image_name, 
    image 
    ) 
    values 
    (
    '$this->image_name', 
    '$image' 
    )"; 
    if(mysql_query($query)){ 
    echo "Insert success"; 
    } 
    else 
    { 
    echo "Insert not success"; 
    } 
    } 

    function get_all_image_list(){ 
    $query = "select *from t_image_upload"; 
    $result = mysql_query($query); 
    return $result; 
    } 

} 
?>

但問題可能規定了在index.php上線63

<td style="text-align:center" style="width:50%;><img src="images/<?php echo $data['image']; ?>" width="400px" height="200px"></td> 
    </tr>

這裏有一些屏幕截圖：

enter image description here

來源

2016-12-19 arclite86

image uploaded successfully successfully？ –

爲什麼所有u'r id的0 ??你看到什麼時候檢查元素？（F12 in chrome） – Mitch

首先，檢查ima ge上傳到文件夾中，然後嘗試給絕對路徑，如

<tr> 
<td style="text-align:center" style="width:50%;> 
<img src="http://localhost/project/images/<?php echo $data['image']; ?>" width="400px" height="200px"> 
</td> 
</tr>

來源

2016-12-19 12:33:50

php上傳圖像和顯示數據庫（錯誤）

回答

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