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用java這是我的HTTP URL我需要使用json請求進行java.net url的獲取。請告訴我,我怎麼能叫,在谷歌的AppEngine

POST HTTPS://www.googleapis.com/admin/directory/v1/group 
MY json request 
{ 
    "email": "[email protected]", 
    "name": "Sales Group", 
    "description": "This is the Sales group." 
} 

我使用目錄API來創建組。

我從來沒有使用URL獲取,所以我不熟悉這一點。 請幫我,我該怎麼做..

這是我的答案我發佈後2小時。由於我的聲望不到10,所以stackoverflow不允許我在8小時之前回答我自己的問題,所以請原諒我長時間的問題。 我試過這個.. 我在傳遞json作爲參數時有點掙扎。這裏是我的代碼

import java.io.IOException; 

import java.io.OutputStreamWriter; 
import java.net.HttpURLConnection; 
import java.net.URL; 
import java.util.logging.Logger; 

import javax.servlet.http.*; 

import com.google.appengine.labs.repackaged.org.json.JSONException; 
import com.google.appengine.labs.repackaged.org.json.JSONObject; 

@SuppressWarnings("serial") 
public class DirectoryApiExampleServlet extends HttpServlet { 
     static Logger log = gger.getLogger(DirectoryApiExampleServlet.class.getName()); 
public void doGet(HttpServletRequest req, HttpServletResponse resp) 
     throws IOException { 
    URL url = new URL("https://www.googleapis.com/admin/directory/v1/groups"); 
    HttpURLConnection connection = (HttpURLConnection) url.openConnection(); 
    connection.setDoOutput(true); 
    connection.setRequestMethod("POST"); 
    connection.setRequestProperty("Content-Type", "application/json"); 
    connection.setRequestProperty("Accept", "application/json"); 
    OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream()); 
    JSONObject json = new JSONObject(); 
    try { 
     json.put("email", "[email protected]"); 
     json.put("name", "Test Group"); 
     json.put("description", "this is a test group"); 
    } catch (JSONException e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 
    } 
    writer.write(json.toString()); 
    writer.flush(); 
    writer.close(); 
    log.info("connection.getResponseCode()"+connection.getResponseCode());   
} 

}

但它給未預期401響應。

我在哪裏犯錯誤?

回答

0

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