無法轉到Jasper服務器上的計劃的第二步

我正在使用32位版本的Jasper Server 4.5.0。無法轉到Jasper服務器上的計劃的第二步

當我點擊填充報表名稱作爲調度服務器報告的第一步請求後接下來，它給了我下面的錯誤：

The server has encountered an error. Please excuse the inconvenience. 
An error has occurred. Please contact your system administrator. (5321)

錯誤日誌以下：

2012-04-09 17:37:38,940 WARN IntrusionDetector,http-8080-2:449 - [SECURITY FAILURE Anonymous:[email protected] -> /ExampleApplication/IntrusionDetector] Invalid input: context=trigger.timezone-ViewRepository_Schedule_OutputSettings_context, type(AlphaUnderscoreForward)=^[\p{L}\p{M}\p{Pc}\/]*$, input=GMT 05:30 
org.owasp.esapi.errors.ValidationException: trigger.timezone-ViewRepository_Schedule_OutputSettings_context: Invalid input. Please conform to regex ^[\p{L}\p{M}\p{Pc}\/]*$ with a maximum length of 100 
    at org.owasp.esapi.reference.validation.StringValidationRule.checkWhitelist(StringValidationRule.java:144) 
    at org.owasp.esapi.reference.validation.StringValidationRule.checkWhitelist(StringValidationRule.java:160) 
    at org.owasp.esapi.reference.validation.StringValidationRule.getValid(StringValidationRule.java:284) 
    at org.owasp.esapi.reference.DefaultValidator.getValidInput(DefaultValidator.java:213) 
    at com.jaspersoft.jasperserver.api.security.validators.ValidatorImpl.validate(ValidatorImpl.java:345) 
    at com.jaspersoft.jasperserver.api.security.validators.ValidatorImpl.validate(ValidatorImpl.java:251) 
    at com.jaspersoft.jasperserver.api.security.WebAppSecurityFilter.validate(WebAppSecurityFilter.java:175) 
    at com.jaspersoft.jasperserver.api.security.WebAppSecurityFilter.doFilter(WebAppSecurityFilter.java:82) 
    at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:411) 
    at com.jaspersoft.jasperserver.war.MultipartRequestWrapperFilter.doFilter(MultipartRequestWrapperFilter.java:90) 
    at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:411) 
    at org.springframework.security.context.HttpSessionContextIntegrationFilter.doFilterHttp(HttpSessionContextIntegrationFilter.java:235) 
    at org.springframework.security.ui.SpringSecurityFilter.doFilter(SpringSecurityFilter.java:53) 
    at org.springframework.security.util.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:411) 
    at org.springframework.security.util.FilterChainProxy.doFilter(FilterChainProxy.java:188) 
    at org.springframework.security.util.FilterToBeanProxy.doFilter(FilterToBeanProxy.java:99) 
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) 
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) 
    at com.jaspersoft.jasperserver.war.util.CharacterEncodingFilter.doFilter(CharacterEncodingFilter.java:67) 
    at org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:236) 
    at org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:167) 
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) 
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) 
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) 
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) 
    at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:558) 
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) 
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) 
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) 
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) 
    at org.apache.coyote.http11.Http11AprProcessor.process(Http11AprProcessor.java:859) 
    at org.apache.coyote.http11.Http11AprProtocol$Http11ConnectionHandler.process(Http11AprProtocol.java:579) 
    at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1555) 
    at java.lang.Thread.run(Thread.java:619) 
2012-04-09 17:37:38,972 WARN JSCommonController,http-8080-2:202 - There was a security error

來源

2012-04-09 Sahar Hassan

您可以閱讀[本期]（http://jasperforge.org/plugins/espforum/view.php?group_id=112&forumid=102&topicid=94962）和[this one]（http://jasperforge.org/plugins /espforum/view.php?group_id=83&forumid=101&topicid=97259）。 – 2012-04-09 12:36:40

這是類型的電子郵件，在我的情況是類型是「類型（AlphaUnderscoreForward）」，你分享的第二篇文章只是我的。 :) – 2012-04-09 12:38:19

我看到:)。您應該將日誌添加到剛剛添加的問題主體 – 2012-04-09 12:41:02

要jasperserver\WEB-INF\classes\esapi\security.properties文件禁用timezone驗證，你可以發表評論（或刪除）該字符串：

trigger.timezone=AlphaDot,AlphaUnderscoreForward,100,true,trigger.timezone-ViewRepository_Schedule_OutputSettings_context

你應該檢查你的timezone服務器上定義的：

默認時區（獲得與Java - java.util.TimeZone.getDefault()）;
帶時區的列表jasperserver\WEB-INF\applicationContext.xmluserTimeZonesList bean的文件，timeZonesIds屬性。

從jasperserver\WEB-INF\classes\esapi\validation.properties文件表達

Validator.AlphaUnderscoreForward=^[\\p{L}\\p{M}\\p{Pc}\\/]*$

僅僅是值驗證正則表達式。

來源

2012-04-10 07:38:54

無法轉到Jasper服務器上的計劃的第二步

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