我需要檢查,如果一個對象爲空或PHP具有價值和研究,我跟這個代碼後:檢查對象爲空或有值
$user = $this->client->findClientByLogin(array("login" => $user_data[0]->username));
if (!is_object($user) && (count(get_object_vars($user)) < 0)) {
$this->client->addClient(array("login" => $user_data[0]->username, "password" => $password));
}
但即使$user
是一個空的對象由於條件不適用,addClient()
未執行。任何人都可以給我一些建議嗎?
編輯:Test1的
我使用此代碼做了一些測試:
echo "Count ".count(get_object_vars($user));
echo "Is object ".!is_object($user);
var_dump($user);
die();
,結果是: 計數: 比較對象:1
object(stdClass)[78]
public 'clientsshared' =>
object(stdClass)[160]
public 'id_client' => int 44
public 'login' => string 'reynierperez-mira' (length=17)
public 'password' => string '' (length=0)
public 'web_password' => string '09bb0def8de1262ac9e5a9b8a5935771' (length=32)
public 'type' => int 8389121
public 'id_tariff' => int 2
public 'account_state' => string '0.0000' (length=6)
public 'tech_prefix' => string '' (length=0)
public 'id_reseller' => int -1
public 'type2' => int 0
public 'type3' => int 0
public 'id_intrastate_tariff' => int -1
public 'id_currency' => int 1
public 'codecs' => int 19
public 'primary_codec' => int 2
public 'free_seconds' => string '' (length=0)
public 'id_tariff_vod' => int 0
public 'video_codecs' => int 0
public 'video_primary_codec' => int 0
public 'fax_codecs' => int 0
public 'fax_primary_codec' => int 0
public 'id_cli_map' => int 0
public 'id_dial_plan' => int 1
public 'id_dial_plan_map' => int 1
public 'id_pbx_company' => int 0
使告訴我,用戶reynierperez-mira
已經存在,所以我不應該輸入條件因爲我不會添加任何用戶,但如果用戶不存在,那麼我將通過在條件上輸入來添加。這個案件有什麼合適的條件?
的Test2:用戶不存在
好吧,我刪除所有用戶,以便findClientByLogin()
回報空的對象。我測試了這種方式:
$user = $this->client->findClientByLogin(array("login" => $user_data[0]->username));
echo "Count " . count(get_object_vars($user));
echo "Is object " . is_object($user);
echo "-----------";
var_dump($user);
die();
這是輸出:
Count 0
Is object 1
-----------
object(stdClass)[78]
所以我改變了條件:
if (is_object($user) && (count(get_object_vars($user)) === 0)) { ...
而現在它的作品!
'count()'永遠不會返回小於0. – Barmar