在MS Access中訂購聯合查詢SQL

Question

好吧我有一個特別討厭的聯合訂購問題，所以我們將不勝感激。

的情況是這樣的：

成員表與以下記錄（實際數據）：

REI882 
YUI987 
POBO37 
NUBS26 
BTBU12 
MZBY10 
TYBW54 

（這些在順序列出我希望他們從我的查詢回來。）

關於這些MemberID的構建有許多業務規則，我認爲這些與這種無關。它們具有歷史意義並且堅如磐石。我困在他們身邊。他們表示會員的資歷。

順序是從最後4個字符的ID完成，上行。就類別而言，ID的前兩個字符完全沒有意義。

所以最上面可能記錄是?? A001（最高級）和可能的最低記錄是?? ZZ99（至少高級）。

當我查詢我的成員表中的名單，我回去必須顯示最高級的頂部......顯然，一個標準的排序不起作用。這是我迄今：

其中第一個查詢與排序成員的ID只有1個字母交易。第二個涉及那些有2個主要字母的人。

SELECT * FROM (

    SELECT Member.ID 
    FROM Member 
    WHERE (((IsNumeric(Mid([Member.ID],4,1)))=-1)) **check the 4th character is a digit 
    ORDER BY (Mid([Member.ID],3,1)), (Mid([Member.ID],4,1)), (Mid([Member.ID],5,1)), (Mid([Member.ID],6,1)) 
) t1 

UNION 

SELECT * FROM (
    SELECT Member.ID 
    FROM Member 
    WHERE (((IsNumeric(Mid([Member.ID],4,1)))=0)) **check the 4th character is a letter 
    ORDER BY (Mid([Member.ID],3,1)), (Mid([Member.ID],4,1)), (Mid([Member.ID],5,1)), (Mid([Member.ID],6,1)) 
) t2 

但是我得到了與聯盟的瘋狂結果！如果我單獨運行每個選擇 - 沒有問題，我的時髦（嚴重依賴訪問中的一些討厭的字符串操作！）排序完全按照我的要求工作。

我明白這是相當複雜的，但我希望我已經清楚地解釋它，有人是因爲某些榮譽爲計算出來！

編輯：從我的查詢結果是看似隨意：

YUI987 
MZBY10 
NUBS26 
BTBU12 
REI882 
POBO37 
TYBW54 

Answer 1

你爲什麼不使用RIGHT功能。

喜歡的東西

SELECT ID 
FROM (
      SELECT ID 
      FROM (
         SELECT Member.ID 
         FROM Member 
         WHERE (((IsNumeric(Mid([Member.ID],4,1)))=-1)) **check the 4th character is a digit 
        ) t1 
      UNION 
      SELECT ID 
      FROM (
         SELECT Member.ID 
         FROM Member 
         WHERE (((IsNumeric(Mid([Member.ID],4,1)))=0)) **check the 4th character is a letter 
        ) t2 
     ) t3 
ORDER BY RIGHT(ID,4) 

Answer 2

如何跳過UNION？

SELECT members.ID 
FROM members 
ORDER BY Right([ID],3), Right(id,4) 

根據新規則，這個混亂可能會奏效。

SELECT 
    Len(IIf([textId] Like "[a-z][a-z][0-9][0-9][0-9][0-9]",Left([textid],2), 
    IIf([textId] Like "[a-z][a-z][a-z][0-9][0-9][0-9]",Left([textid],3), 
    IIf([textId] Like "[a-z][a-z][a-z][a-z][0-9][0-9]",Left([textid],4),"_")))) AS Ln, 

    IIf(textId Like "[a-z][a-z][0-9][0-9][0-9][0-9]",Left(textid,2), 
    IIf(textId Like "[a-z][a-z][a-z][0-9][0-9][0-9]",Left(textid,3), 
    IIf(textId Like "[a-z][a-z][a-z][a-z][0-9][0-9]",Left(textid,4),"_"))) AS Alpha, 

    IIf(textId Like "[a-z][a-z][0-9][0-9][0-9][0-9]",Val(Right(textid,4)), 
    IIf(textId Like "[a-z][a-z][a-z][0-9][0-9][0-9]",Val(Right(textid,3)), 
    IIf(textId Like "[a-z][a-z][a-z][a-z][0-9][0-9]",Val(Right(textid,2)),0))) AS Numbr, 

    table.textid 
FROM table 
ORDER BY 
    Len(IIf([textId] Like "[a-z][a-z][0-9][0-9][0-9][0-9]",Left([textid],2), 
    IIf([textId] Like "[a-z][a-z][a-z][0-9][0-9][0-9]",Left([textid],3), 
    IIf([textId] Like "[a-z][a-z][a-z][a-z][0-9][0-9]",Left([textid],4),"_")))), 

    IIf(textId Like "[a-z][a-z][0-9][0-9][0-9][0-9]",Left(textid,2), 
    IIf(textId Like "[a-z][a-z][a-z][0-9][0-9][0-9]",Left(textid,3), 
    IIf(textId Like "[a-z][a-z][a-z][a-z][0-9][0-9]",Left(textid,4),"_"))), 

    IIf(textId Like "[a-z][a-z][0-9][0-9][0-9][0-9]",Val(Right(textid,4)), 
    IIf(textId Like "[a-z][a-z][a-z][0-9][0-9][0-9]",Val(Right(textid,3)), 
    IIf(textId Like "[a-z][a-z][a-z][a-z][0-9][0-9]",Val(Right(textid,2)),0))) 

Answer 3

在SELECT聲明ORDER BY是UNION與另一SELECT是不正確的。

見指定條件定單here

您可以使用此：

SELECT ID FROM( 
(SELECT Member.ID,1 AS T,Left([Member.ID],2) AS Part1, Right([Member.ID],4) AS Part2 
    FROM Member 
    WHERE (((IsNumeric(Mid([Member.ID],3,1)))=-1)))  
UNION  
    (SELECT Member.ID,2 AS T,Left([Member.ID],3) AS Part1, Right([Member.ID],3) AS Part2 
    FROM Member 
    WHERE (((IsNumeric(Mid([Member.ID],4,1)))=-1) and ((IsNumeric(Mid([Member.ID],3,1)))=0)))  
UNION  
    (SELECT Member.ID,3 AS T,Left([Member.ID],4) AS Part1, Right([Member.ID],2) AS Part2 
    FROM Member 
    WHERE (((IsNumeric(Mid([Member.ID],5,1)))=-1) and ((IsNumeric(Mid([Member.ID],4,1)))=0)))  

ORDER BY T,Part1,Part2) 

@Justin柯克：我不知道什麼是你的問題完全一樣。但我希望它可以幫助你