我正在使用掃描器方法嘗試獲取文件輸入。問題是我只在First name和Last name之後得到第一個int。這裏是文本文件:解析文件輸入中的數字
John Doe 12 6 8 15 35 16 17 4 12 54
Mark Doe 16 67 8 12 35 19 78 3 12 101
Johnnie Smarts 20 10 10 20 40 100 20 10 20 100
Frank Noshow
Molly Guess 2 5 6 7 2 4 7 8 9 10
我有這麼多的代碼,這樣做的遠:
import java.io.*;
import java.util.*;
import static java.lang.Math.*;
import static java.lang.System.out;
public class StudentTester
{
public static void main (String[] args) throws IOException
{
Scanner kb = new Scanner(System.in);
System.out.println("\tWelcome.. ");
System.out.println(" Please enter the file name. ");
String filename = kb.nextLine();
Scanner fileReader = new Scanner(new File(filename));
//created a scanner object with a file object.
//Creat a String array to hold each lince of the file.
String [] s = new String [10000]; //prepared for a 100 lines of text.
int linesOfText = -1;
int score[] = new int[10];
while (fileReader.hasNextLine())//while the file has any lines.
{
linesOfText++;
s[linesOfText] = fileReader.nextLine();
//This places the first line of the file in the s array.
//System.out.println(s[linesOfText]);//for testing purposes..
}
fileReader.close();//close the Scanner.
for(int i=0;i<=linesOfText;i++){
Scanner sc = new Scanner(s[i]);
String fN = sc.next();
String lN = sc.next();
if(sc.hasNext()){
score[i] = sc.nextInt();
}
else {
System.out.println(" opps, there is no score here... ");
}
Student stu = new Student(fN,lN,score);
System.out.println(score[i]);
}
}
}
你如何期待* *它來讀取一個值嗎?你只有一次'nextInt',並根據你正在記錄的記錄填充'score [i]',而不是某個特定的學生。我建議提取代碼,將單個學生的數據讀入單獨的方法 - 這會使它簡單得多。 –
Thxx用於編輯! –