Python Array Diff

Question

編寫一個函數或程序，它將採用2個整數「當前」和「目標」數組，並生成2個數組，表示添加列表和刪除列表，以便將添加和刪除應用於「當前「數組將產生」目標「數組。

例如，給定以下 輸入：

current = [1, 3, 5, 6, 8, 9] 

target = [1, 2, 5, 7, 9] 

的輸出將是：

additions: [2, 7] 

deletions: [3, 6, 8] 

所以，以下爲真：

電流（[1， （3,5,7,9）] +添加物（[2,7]） - 刪除物（[3,6,8]）=目標物（[1,2,5,7,9]）

解決方案：

到目前爲止，我有這樣的：

--------------------------- 

# import array function 
from array import array 

# create an integer array named current 
current = array('i', [1, 3, 5, 6, 8, 9]) 

# add items from additions list into current array using the fromlist() method 
additions = [2, 7] 
current.fromlist(additions) 

# remove items on deletions list from current array using the.  remove() method 
current.remove(3) 
current.remove(6) 
current.remove(8) 

---

Answer 1

它會爲你工作...

def addlist(current,target): 
     add = [] 
     intersection = set(current) & set(target) 
     for i in target: 
       if i not in intersection: 
         add.append(i) 
     return add 

def removeList(current,target): 
     remove = [] 
     intersection = set(current) & set(target) 
     for i in current: 
       if i not in intersection: 
         remove.append(i) 
     return remove 

def main(): 
     current = [1, 3, 5, 6, 8, 9] 
     target = [1, 2, 5, 7, 9] 
     print(addlist(current,target)) 
     print(removeList(current,target)) 

if __name__=="__main__": 
     main() 

Answer 2

下面一個應該很容易理解。

>>> current = [1, 3, 5, 6, 8, 9] 
>>> target = [1, 2, 5, 7, 9] 
>>> set(current) & set(target) 
set([1, 5, 9]) 
>>> unique = list(set(current) & set(target)) 
>>> additions = [i for i in target if i not in unique] 
>>> additions 
[2, 7] 
>>> deletions = [i for i in current if i not in unique] 
>>> deletions 
[3, 6, 8] 
>>> 

Answer 3

這也能發揮作用。

current = [1, 3, 5, 6, 8, 9] 
target = [1, 2, 5, 7, 9] 
additions=[x for x in target if x not in current] 
deletions=[x for x in current if x not in target]