下載/保存可從給定的URL直接獲得的文件

Question

我有像this link這樣的鏈接，它直接詢問要保存的文件名，並開始在瀏覽器中下載。

如何以編程方式下載或保存此文件？

我試着用下面的方法：

static void DownloadFile(String url, String fileName) throws MalformedURLException, IOException 
{ 
    url = "http://dbpedia.org/sparql?default-graph-uri=http%3A%2F%2Fdbpedia.org&query=DESCRIBE+<"+ url +">&format=text%2Fcsv"; 
    URL link = new URL(url); //The file that you want to download 

    InputStream in = new BufferedInputStream(link.openStream()); 
    ByteArrayOutputStream out = new ByteArrayOutputStream(); 
    byte[] buf = new byte[1024]; 
    int n = 0; 
    while (-1!=(n=in.read(buf))) 
    { 
     out.write(buf, 0, n); 
    } 
    out.close(); 
    in.close(); 
    byte[] response = out.toByteArray(); 

    FileOutputStream fos = new FileOutputStream(fileName); 
    fos.write(response); 
    fos.close(); 
    System.out.println("Finished"); 
} 

但這保存只具有第一線「」對象「‘上游’，‘對象’ 」，而不是完整的文件的文件。

編輯：

正如在回答中我嘗試以下建議，但也只給了該文件的第一行：

static void DownloadFile(String s_url, String fileName) throws MalformedURLException, IOException 
{ 
    s_url = "http://dbpedia.org/sparql?default-graph-uri=http%3A%2F%2Fdbpedia.org&query=DESCRIBE+<"+ s_url +">&format=text%2Fcsv"; 
    //url = "http://dbpedia.org/data/Sachin_Tendulkar.rdf"; 
    try { 
     URL url = new URL(s_url); //The file that you want to download 

     // read text returned by server 
     BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream())); 
     PrintWriter out = new PrintWriter(fileName); 

     String line; 
     while ((line = in.readLine()) != null) { 
      out.println(line); 
     } 
     in.close(); 
     out.close(); 
    } 
    catch (MalformedURLException e) { 
     System.out.println("Malformed URL: " + e.getMessage()); 
    } 
    catch (IOException e) { 
     System.out.println("I/O Error: " + e.getMessage()); 
    } 
    System.out.println("Finished"); 
} 

編輯：

我也嘗試了Apache FileUtils，但是這也只給出了文件的第一行。

static void DownloadFile(String s_url, String fileName) throws MalformedURLException, IOException 
{ 
    s_url = "http://dbpedia.org/sparql?default-graph-uri=http%3A%2F%2Fdbpedia.org&query=DESCRIBE+<"+ s_url +">&format=text%2Fcsv"; 
    URL url = new URL(s_url); //The file that you want to download 
    FileUtils.copyURLToFile(url, new File(fileName)); 
    System.out.println("Finished"); 
} 

Answer 1

，如果你想下載一個文件

，阿帕奇百科全書剛纔你在找什麼，偉大工程！

org.apache.commons.io.FileUtils.copyURLToFile(new URL("URL")), new File("path/to/file")); 

如果URL返回文本，你可以嘗試這樣的事：

try { 
     URL url = new URL("http://www.google.com:80/"); 

     // read text returned by server 
     BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream())); 
     PrintWriter out = new PrintWriter("filename.txt"); 

     String line; 
     while ((line = in.readLine()) != null) { 
      out.println(line); 
     } 
     in.close(); 
     out.close(); 
    } 
    catch (MalformedURLException e) { 
     System.out.println("Malformed URL: " + e.getMessage()); 
    } 
    catch (IOException e) { 
     System.out.println("I/O Error: " + e.getMessage()); 
    }