我有一個PHP頁面,腳本正在搜索某個特定名稱的表是否存在。如果沒有表格,它會顯示合適的信息。如果存在表格,則會向其添加一些數據並顯示成功會話消息。現在,我想顯示會話消息爲Data added to ABC (name of the chosen table) successfully
。相反,我得到的會話消息爲Data added to $table sucessfully
。如何在創建的表的會話消息中回顯變量
請幫忙。以下是我的代碼 -
<?php
require_once("config.php");
require_once("config2.php");
$keyQ = $db->query("SELECT * FROM Collection where id =
$Id");
$kVal = $kewyQ->fetch(PDO::FETCH_ASSOC);
$table = trim($kVal['words']);
try
{
// Select 1 from table_name will return false if the table does not exist.
$value = $db2->query("select 1 from `$table` LIMIT 1");
}catch (PDOException $e) {
echo "$table does not exist";
exit;
}
if($value !== FALSE)
{
........
........
session_start();
$_SESSION['success'] = 'Data added to $table successfully.';
header('location:list2.php');
}
?>
'$ _SESSION ['success'] ='數據已添加到'。$ table'中。 ';' – ASR