java.io.FileNotFoundException（拒絕訪問）錯誤？但文件正在存儲

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我收到一個錯誤HTTP狀態500 - java.io.FileNotFoundException： C：\ SAM \ IMAGES（訪問被拒絕），同時保存圖像在文件'IMAGES'中。我嘗試了所有的事情，如更改文件的權限，並試圖將其保存在不同的文件夾中。奇怪的是，我的圖像實際上被存儲在我上面提到的文件中。但是爲什麼仍然它顯示錯誤？如何解決這個錯誤？Tomcat是用戶的所有權。java.io.FileNotFoundException（拒絕訪問）錯誤？但文件正在存儲

My Code: 
MySampleUpload.jsp 
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" 
    pageEncoding="ISO-8859-1"%> 
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> 
<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> 
<title>Insert title here</title> 
</head> 
<body> 
<form action="FileUploadServlet" method="post"enctype="multipart/form-data"> 
    <div class="btn btn-success btn-file"> 
    <i class="fa fa-cloud-upload"></i> 
      Browse 
    <input type="file" name="file" /> 
    </div> 
    <button type="submit" value="submit" name='submit'>submit</button>` 
    </form> 
</body> 
</html> 

FileUploadServlet.java 



import java.io.File; 
import java.io.IOException; 

import javax.imageio.stream.FileImageOutputStream; 
import javax.servlet.ServletException; 
import javax.servlet.annotation.MultipartConfig; 
import javax.servlet.annotation.WebServlet; 
import javax.servlet.http.HttpServlet; 
import javax.servlet.http.HttpServletRequest; 
import javax.servlet.http.HttpServletResponse; 
import javax.servlet.http.Part; 
import java.io.RandomAccessFile; 

/** 
* Servlet implementation class FileUploadServlet 
*/ 
@WebServlet("/FileUploadServlet") 
@MultipartConfig(fileSizeThreshold=1024*1024*10, // 10 MB 
maxFileSize=1024*1024*50,  // 50 MB 
maxRequestSize=1024*1024*100)  // 100 MB 
public class FileUploadServlet extends HttpServlet { 
    private static final long serialVersionUID = 1L; 

    /** 
    * @see HttpServlet#HttpServlet() 
    */ 
    private static final String UPLOAD_DIR="IMAGES"; 
    public FileUploadServlet() { 
     super(); 
     // TODO Auto-generated constructor stub 
    } 


    /** 
    * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response) 
    */ 
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 
     // TODO Auto-generated method stub 
     response.getWriter().append("Served at: ").append(request.getContextPath()); 
    } 

    /** 
    * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response) 
    */ 
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 
     // TODO Auto-generated method stub 
     //gets absolute path of the web application 
     //String applicationPath=request.getServletContext().getRealPath(""); 
     //construct path of the directory to save the uploaded file 
     String UploadFilePath="C:/sam"+File.separator+UPLOAD_DIR; 
     //creates the file directory if it doesn't exist 
     File FileSaveDir=new File(UploadFilePath); 

    if(!FileSaveDir.exists()) 
     { 
      FileSaveDir.mkdirs(); 
     } 

     System.out.println("Upload file Diiirectory"+FileSaveDir.getAbsolutePath()); 
     String fileName=null; 
     //get all parts from request and write it to the file on the server 
     for(Part part:request.getParts()) 
     { 
      fileName=getFileName(part); 

      part.write(UploadFilePath + File.separator + fileName); 

     } 
     System.out.println("File Uploaded successfully"); 
     request.setAttribute("message",fileName+"file uploaded successfully"); 

     getServletContext().getRequestDispatcher("/response.jsp").forward(request, response); 
    } 
    private String getFileName(Part part) 
    { 
    String ContentDisp=part.getHeader("Content-Disposition"); 
    System.out.println("content-disposition-header"+ContentDisp); 
    String[] tokens = ContentDisp.split(";"); 
    for (String token : tokens) { 
     if (token.trim().startsWith("filename")) { 
      return token.substring(token.indexOf("=") + 2, token.length()-1); 

     } 
    } return ""; 
    }}

來源

2017-01-31 Sam

而所有沒有任何代碼？ – Axel

可能會添加一些代碼行，並顯示錯誤顯示的位置將有所幫助，以及提及哪個用戶是在at下運行的tomcat以及目錄的權限是什麼 – JChrist

您是否嘗試過調試它？上傳單個文件時請求中有多少部分？所有這些部分都包含'fileName'嗎？如果'getFileName'返回一個空字符串，你會怎麼想？ – JChrist

你的部件對象迭代2次，從第1次獲取文件名到第2次它是空的。所以檢查部件中的文件名爲null。替換此零件。

for (Part part : request.getParts()) { 
      fileName = getFileName(part); 
      if (fileName != null && !"".equals(fileName)) { 
       part.write(UploadFilePath + File.separator + fileName); 
      } 

     }

來源

2017-01-31 07:22:25

謝謝你，會試試這個:) – Sam

謝謝你soo ...它工作得很好... :) @Sanjay Patel – Sam

但是我沒有得到你說的東西..如何重複它的兩次..我是初學者在java ..如果你解釋一點點，這將是很容易理解。 – Sam

也可以使用下面的代碼，其中表單組件和文件組件是分開的。

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 
    try { 
     List<FileItem> items = new ServletFileUpload(new DiskFileItemFactory()).parseRequest(request); 
     for (FileItem item : items) { 
      if (item.isFormField()) { 
       // Process regular form field (input type="text|radio|checkbox|etc", select, etc). 
       String fieldname = item.getFieldName(); 
       String fieldvalue = item.getString(); 
       // ... (do your job here) 
      } else { 
       // Process form file field (input type="file"). 
       String fieldname = item.getFieldName(); 
       String filename = FilenameUtils.getName(item.getName()); 
       InputStream filecontent = item.getInputStream(); 
       // ... (do your job here) 
      } 
     } 
    } catch (FileUploadException e) { 
     throw new ServletException("Cannot parse multipart request.", e); 
    } 

    // ... 
}

來源

2017-01-31 11:09:47

非常感謝你的時間，現在我明白了.. :) – Sam

java.io.FileNotFoundException（拒絕訪問）錯誤？但文件正在存儲

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