我做了一個應用程序,我可以通過正則表達式在匹配器的幫助下獲得字段值...我做了一個方法,在該方法中,我傳遞一個字段並獲得響應。在字符串今天我得到了一些奇怪的行爲,我的答覆我得到了AgentId = 25001220052805950和匹配器後,我得到fake
,所以我必須檢查名稱中包含「AgentId」的字段是否存在並驗證值。問題與正則表達式
所需的字段: SecondaryAgentId=fake;
PrimaryAgentId=fake;
性反應:
IsPrimaryAgentId=true; AgentId=25001220052805950; MerchantID=19; Cashier=michael; IsManualPayment=1; UserID=GraceRose; Password=rose1234; AmountUserEntered=2; AmountApproved=0; AmountDifference=0; Amount=0; CustomerNameAttempts=0; ProductID=Agriculture; InvoiceID=inv7443; SiteUrl=http://www.thcelink.com/index.php/shoping/checkout/step/step-1; ReturnURL=http://220.2.3:2027/Customer/Thanks.aspx; ResponseType=1; PrimaryAgentId=fake; PrimaryCurrencyCode=fake; SecondaryAgentId=fake; SecondaryCurrencyCode=fake; MerchantName=GraceRose; [email protected]; Query1Attempts=0; MerchantTransactionID=543; MerchantTransactionSequenceID=246; txtAmtIsVisible=false; isQuery1Executed=false; isQuery2Executed=false; Voucher=fake; Passcode=fake; Error=fake; QueryType=fake; Payer=fake; CurrencyName=fake; CurrencySymbol=fake; CustomerName=fake; EmailBody=fake; ErrorText=fake; CustomerEmailID=fake; NavigatePageValue=0; IsCustomerInsertSucess=false; IdType=fake; IdNumber=fake; AggregateAttempts=0; Voucher2=fake; PassCode2=fake; Voucher3=fake; PassCode3=fake; TransCode=0; TransactionDate=2012-06-11T12:04:52.921875+05:30; NumberInWords=fake; MerchantCompany=fake; InvoiceNumber=fake; OverPaidAmount=0; InsufficientAmount=0; OverPaymentForEmail=fake; RedirectPage=false;
更新::
private String GetString1(String strManualproResponce2, String paternField) {
// TODO Auto-generated method stub
String s = null;
if(paternField.equalsIgnoreCase("AgentId"))
{
Pattern pinPattern2 = Pattern.compile("^"+paternField + "=(.*?);");
ArrayList<String> pins2 = new ArrayList<String>();
Matcher m2 = pinPattern2.matcher(strManualproResponce2);
while (m2.find()) {
pins2.add(m2.group(1));
s = m2.group(1);
}
}else
{
Pattern pinPattern2 = Pattern.compile(paternField + "=(.*?);");
ArrayList<String> pins2 = new ArrayList<String>();
Matcher m2 = pinPattern2.matcher(strManualproResponce2);
while (m2.find()) {
pins2.add(m2.group(1));
s = m2.group(1);
}
}
return s;
}
請提供一些你想要的答案和錯誤答案的示例你已經有的代碼 –
我有更新...... –
什麼是'paternField'? –