如何上傳多個文件，創建文件夾並將文件放置在那裏PHP

Question

好吧，我可以成功上傳1個文件，使其在主文件夾內創建一個新文件夾。然後將文件放在那裏。

但是我很難做多個文件到同一個文件夾。

我要上傳2個文件，看起來像這樣：

文檔/ 1 /然後將文件在這裏。

是什麼樣子：

文檔/ 1

HTML：

<form action="upload.php" method="post" enctype="multipart/form-data"> 
     Select image to upload:<br/> 
     <input type="file" name="fileToUpload" id="fileToUpload"><br/> 
     <input type="file" name="fileToUpload" id="fileToUpload"><br/> 
     <input type="submit" value="Upload Image" name="submit"> 
    </form> 

PHP：

<?php 
$number = 1; 
$target_dir = "docs/"; 
$new = mkdir($target_dir . $number . "/"); 
$target_file = $target_dir . $number . "/"; 

$uploadOk = 1; 
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION); 
// Check if image file is a actual image or fake image 

    // Check if file already exists 
    if (file_exists($target_file)) { 
     echo "Sorry, file already exists."; 
     $uploadOk = 0; 
    } 
    // Check file size 
    if ($_FILES["fileToUpload"]["size"] > 500000) { 
     echo "Sorry, your file is too large."; 
     $uploadOk = 0; 
    } 
    // Allow certain file formats 
    if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg" 
    && $imageFileType != "gif") { 
     echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed."; 
     $uploadOk = 0; 
    } 
    // Check if $uploadOk is set to 0 by an error 
    if ($uploadOk == 0) { 
     echo "Sorry, your file was not uploaded."; 
    // if everything is ok, try to upload file 
    } else { 
     foreach($_FILES['fileToUpload']['name'] as $file => $uploaded_file){ 
      move_uploaded_file($_FILES['fileToUpload']['tmp_name'], $target_file . $uploaded_file); 
     } 
} 
?> 

任何想法？

編輯工作：

 <input type="file" name="pictures[]" /><br/> 
     <input type="file" name="pictures[]" /><br/> 
     <input type="file" name="pictures[]" /><br/> 
     <input type="submit" value="Send" /> 

    </form> 

$target_dir = "docs/"; 
$dir=glob($target_dir."/*",GLOB_ONLYDIR); 
$number = count($dir) + 1; 
$new = mkdir($target_dir . $number . "/"); 
$target_file = $target_dir . $number . "/"; 


foreach ($_FILES["pictures"]["name"] as $key => $Name) 
{ 
     $tmp_name = $_FILES["pictures"]["tmp_name"][$key]; 
     $name = $_FILES["pictures"]["name"][$key]; 
     move_uploaded_file($tmp_name, $target_file . "$name"); 
} 

Answer 1

首先改變你的文件輸入（注意，ID應該是唯一的所有元素，以避免JavaScript的問題）：

<input type="file" name="fileToUpload[]" id="fileToUpload_0"> 

既然你要上傳的文件陣列。

foreach($_FILES['fileToUpload'][$name] as $index=>$uploaded_file) { 
    move_uploaded_file(
      $_FILES['fileToUpload']['tmp_name'][$index], 
     $target_file.$uploaded_file); 
} 

更新：曾在語言和文件處理邏輯一時的組合。