Python打印不需要的額外換行符

Question

爲什麼當我運行下面的代碼時，Python總是打印額外的換行符？我試圖重新編寫代碼以消除任何意外的空白，但它仍然會打印出一個額外的新行。有人知道爲什麼謝謝。

def main(): 
    names_in()       #This function import the file and read all the content and put the content into a list. 

    print_names(names_in)  # Before the names are sorted. 

def names_in(): 
    infile = open('names.txt','r') 
    names_list = []     #empty list. 
    names = infile.readline() # read contents. 

    #loop for continue to read. 
    while names != '': 
     names = infile.readline()  #continue to the next name. 
     names = names.rstrip('\n') #return a copy of the string which all \n has been stripped from the end of the string. 
     names_list.append(names) #write names in the file into a list. 
    infile.close() 

    return names_list      #return the list back to the function. 



def print_names(names_in):  #This function will print out the names in the list one per line, single-spaced. 
    for item in names_in(): 
     print(item) 


main() 

這在我的輸入文件：

Riggs, Jerry 
Stone, Ruby 
Wood, Holly 
Dover, Ilene 
Funt, Ella 
Storm, Wayne 
Lowe, Lyle 
Free, Bjorn 
Caine, Candy 
Carr, Rex 
Downs, Mark 
Twain, Lionel 
Thorn, Rose 
Shore, Rocky 
Bush, Rose 
Waters, Muddy 
Graves, Doug 
Stone, Roxanne 
Rivers, Wade 

Answer 1

你的代碼打印額外的換行符的原因是因爲在names_in功能的最後一次迭代中，變量names是``，它被附加到names_list的末尾，導致print_names函數在最後運行print ''，這會打印一個額外的換行符。