在白色空間分割字符串

Question

我有這個奇怪的格式化文本文件我想讀，我不知道如何告訴python，每行以分隔符開頭。

在文本文件中的一行看起來像：

 3.146 -1.339  .358 29.214 

該文件使用5個空格作爲分隔符。我怎樣才能將每行讀入一個包含4個項目的列表？

Answer 1

使用split與strip相結合，去除多餘的空白：

my_file_data = "  3.146 -1.339  .358 29.214" 
data = my_file_data.strip().split('  ') 
# do stuff with your data 
print(data[0]) 

Answer 2

你可以閱讀每一行成一個列表，使用以下4項：

with open(filename, 'r') as f: 

    # this will read in each row as: 
    # 
    # ['3.146', '-1.339', '.358', '29.214'] 
    # 
    # so `lines` will contain 
    # 
    # [['3.146', '-1.339', '.358', '29.214'], ...] 
    lines = map(str.split, f.readlines()) 

    # or alternatively, as @jez mentioned, it may be more readable to use 
    lines = [ line.split() for line in lines ] 

    # you'll then likely want to convert them to floats 
    # 
    # this will give you: 
    # 
    # [[3.146, -1.339, 0.358, 29.214], ...] 
    data = [ map(float, split_line) for split_line in lines ] 

Answer 3

這是你的分隔符：

delimiter=' '

然後你只需使用的分隔符

lineoftext.split(delimiter)