我試圖從多項式中提取coeffecients的值和指數。我已經成功地使用strtok
來提取係數。我應用相同的概念來找到指數,但我不知道如何使用strtok
來提取字符串後的分隔符或跳過第一個字符,而strtok
是我知道的唯一的提取工具。使用c字符串從多項式C++中提取指數
這是主要的功能
#include <iostream>
#include <cctype>
#include <cstring>
#include <cstdlib>
#include <string>
using namespace std;
void extractCoeff (char *str, char *copy);
void extractExp (char *str, char *copy);
int main()
{
const int SIZE = 150; // size for string input
char *string;
string = new char[SIZE];
cout << "Enter the polynomial\n"<<"minus sign must not have a blank with a coeff";
cin.ignore();
cin.getline(string, SIZE); // input string example: -4x^0 + x^1 + 4x^3 -3x^4
char *copy1;
copy1 = new char[SIZE];
strcpy(copy1, string);
extractCoeff(string, copy1);
cout << endl << endl;
char *copy2;
copy2 = new char[SIZE];
strcpy(copy2, string);
extractExp(string, copy2);
return 0;
}
這是函數提取係數_(工作)
void extractCoeff (char *str, char *copy)
{
char *p = strtok(str, " +"); // extract the first time
char *search;
int counter = 0;
while (p)
{
search = strstr(p, "x^");
cout << "Token: " << p << endl;
cout << "Search " << search << endl;
p = strtok(NULL, " +");
counter++;
}
cout << copy << endl;
// find coeff
int *coefficient;
coefficient = new int[counter];
p = strtok(copy, " +"); // extract the second time to find coeff
int a = 0;
while (p)
{
cout << "p: " << p << endl;
long coeff;
if (*p == 'x')
{
coeff = 1;
}
else if (*p == NULL)
{
coeff = 0;
}
else
{
char *endptr;
coeff = strtol(p, &endptr, 10);
}
coefficient[a] = coeff;
p = strtok(NULL, " +");
a++;
}
for (int i = 0; i < counter; i++)
cout << coefficient[i] << endl;
}
這是提取指數(不工作)
void extractCoeff (char *str, char *copy)
{
char *p = strtok(str, " +"); // extract the first time
char *search;
int counter = 0;
while (p)
{
search = strstr(p, "x^");
cout << "Token: " << p << endl;
cout << "Search " << search << endl;
p = strtok(NULL, " +");
counter++;
}
cout << copy << endl;
// find coeff
int *coefficient;
coefficient = new int[counter];
p = strtok(copy, " +"); // extract the second time to find coeff
int a = 0;
while (p)
{
cout << "p: " << p << endl;
long coeff;
if (*p == 'x')
{
coeff = 1;
}
else if (*p == NULL)
{
coeff = 0;
}
else
{
char *endptr;
coeff = strtol(p, &endptr, 10);
}
coefficient[a] = coeff;
p = strtok(NULL, " +");
a++;
}
for (int i = 0; i < counter; i++)
cout << coefficient[i] << endl;
}
void extractExp (char *str, char *copy)
{
char *p = strtok(str, " x^"); // extract the first time
//char *search;
int counter = 0;
while (p)
{
//search = strstr(p, "x^");
//cout << "Token: " << p << endl;
//cout << "Search " << search << endl;
p = strtok(NULL, " x^");
counter++;
}
cout << copy << endl;
// find coeff
int *exp;
exp = new int[counter];
p = strtok(copy, " x^"); // extract the third time
int b = 0;
while (p)
{
cout << "p2: " << p << endl;
int expVal;
if (*p == NULL)
{
expVal = 0;
}
else
{
char *endptr;
expVal = strtol(p, &endptr, 10);
}
exp[b] = expVal;
p = strtok(NULL, " x^");
b++;
}
for (int i = 0; i < counter; i++)
cout << exp[i] << endl;
}
你應該告訴我們它「不起作用」。你期望看到什麼,你會得到什麼? – JoergB 2013-03-01 11:35:48
也許更好的主意是使用正則表達式解析完整的輸入。您可以使用例如['boost :: regex'](http://www.boost.org/doc/libs/1_53_0/libs/regex/doc/html/index.html),或者新的C++中的'std :: regex', +11標準。 – 2013-03-01 11:46:47