獲得兩個指定的字母

Question

對於Objective-C的，我怎麼找出給定的兩個字母之間的字母之間的所有字母。例如，對於兩個字母A和d，我應該得到A，B，C，D

Answer 1

，你可以嘗試這樣的代碼：

NSString *start = @"A"; 
NSString *end = @"D"; 
unichar startChar = [start characterAtIndex:0]; 
unichar endChar = [end characterAtIndex:0]; 
for (unichar c = startChar; c <= endChar; c++) 
{ 
    NSLog(@"%c",c); 
} 

結果：

2012-12-17 19:01:36.259 Test[7492:907] A 
2012-12-17 19:01:36.263 Test[7492:907] B 
2012-12-17 19:01:36.264 Test[7492:907] C 
2012-12-17 19:01:36.265 Test[7492:907] D 

希望這有助於。

Answer 2

最短的代碼將是：

for (char c = 'a'; c <= 'd'; c++) 
    NSLog(@"char = %c", c); 

Answer 3

首先

unichar StartChar = [@"R" characterAtIndex:0]; 
unichar EndChar = [@"X" characterAtIndex:0]; 
for (unichar Result = StartChar; c <= EndChar; c++) 
{ 
    NSLog(@"%c",Result); 
} 

二

NSString *string = @"ABCDEFGHIJKLMNOPQRSTUVWXYZ"; 

int startIndex = [string rangeOfString:@"A"].location; 
NSString *subString = [string substringFromIndex:startIndex]; 

int EndIndex = [subString rangeOfString:@"H"].location; 

NSString*result = [subString substringToIndex:EndIndex+1]; 
NSLog(@"%@",result); 

三

NSArray *string = [[UILocalizedIndexedCollation currentCollation] sectionTitles]; 
int startIndex = [string indexOfObject:@"D"]; 
int EndIndexIndex = [string indexOfObject:@"I"]; 

for (int i=startIndex; i<=EndIndexIndex; i++) 
{ 
    NSLog(@"%@",[string objectAtIndex:i]); 
}