(這是一項正在進行的工作。我不知道是否有人能對其進行改進)的目標C在iOS上使用IPv6的DNS解析僅同步?
,可以很容易地解決與NSHost主機名。
[[NSHost hostWithName:@"www.google.com"] address]
很遺憾,iOS(iPhone)僅包含一個私有版本的NSHost。
我發現有很多方法可以與其他對象或方法做到這一點,但它們都只在結果中獲得IPv4地址。所以這裏是目前唯一有效的方法。
我第一次嘗試使用異步CFHostStartInfoResolution與bdunagan一樣,但未能使其適應IPv6。
你們中的一些人會欣賞得到一個方法的工作,所以這裏是一個,但如果你知道一種方法,這將是異步的,我會很高興瞭解它...因爲我現在使用Popup來提醒關於可能緩慢蜂窩連接發生
/**
Give the IPs corresponding to a Hostname
Sometime only 1 IPv4 is shown even if there's more.
Sometime only 1 IPv6 is shown even if there's more.
Certainly due to iOS Memory optimisation when locally cached
@author Christian Gonzalvez, http://wiki.gonzofamily.com
@param hostName A hostname
@return an Array of NSString of all the corresponding IP addresses. The first
is the Canonical name, the following are IPs (all NSString)
*/
+ (NSArray *)addressesForHostname:(NSString *)hostname
{
const char* hostnameC = [hostname UTF8String];
struct addrinfo hints, *res;
struct sockaddr_in *s4;
struct sockaddr_in6 *s6;
int retval;
char buf[64];
NSMutableArray *result; //the array which will be return
NSMutableArray *result4; //the array of IPv4, to order them at the end
NSString *previousIP = nil;
memset (&hints, 0, sizeof (struct addrinfo));
hints.ai_family = PF_UNSPEC;//AF_INET6;
hints.ai_flags = AI_CANONNAME;
//AI_ADDRCONFIG, AI_ALL, AI_CANONNAME, AI_NUMERICHOST
//AI_NUMERICSERV, AI_PASSIVE, OR AI_V4MAPPED
retval = getaddrinfo(hostnameC, NULL, &hints, &res);
if (retval == 0)
{
if (res->ai_canonname)
{
result = [NSMutableArray arrayWithObject:[NSString stringWithUTF8String:res->ai_canonname]];
}
else
{
//it means the DNS didn't know this host
return nil;
}
result4= [NSMutableArray array];
while (res) {
switch (res->ai_family){
case AF_INET6:
s6 = (struct sockaddr_in6 *)res->ai_addr;
if(inet_ntop(res->ai_family, (void *)&(s6->sin6_addr), buf, sizeof(buf))
== NULL)
{
NSLog(@"inet_ntop failed for v6!\n");
}
else
{
//surprisingly every address is in double, let's add this test
if (![previousIP isEqualToString:[NSString stringWithUTF8String:buf]]) {
[result addObject:[NSString stringWithUTF8String:buf]];
}
}
break;
case AF_INET:
s4 = (struct sockaddr_in *)res->ai_addr;
if(inet_ntop(res->ai_family, (void *)&(s4->sin_addr), buf, sizeof(buf))
== NULL)
{
NSLog(@"inet_ntop failed for v4!\n");
}
else
{
//surprisingly every address is in double, let's add this test
if (![previousIP isEqualToString:[NSString stringWithUTF8String:buf]]) {
[result4 addObject:[NSString stringWithUTF8String:buf]];
}
}
break;
default:
NSLog(@"Neither IPv4 nor IPv6!");
}
//surprisingly every address is in double, let's add this test
previousIP = [NSString stringWithUTF8String:buf];
res = res->ai_next;
}
}else{
NSLog(@"no IP found");
return nil;
}
return [result arrayByAddingObjectsFromArray:result4];
}
NB的下一個凍結:我注意到,大多數的只返回1 IPv6的時候,我懷疑這是由於iOS的內存優化時,本地緩存。如果你一次又一次地運行這個方法,有時候你有3個IPv6,但是你只有1個IPv4。
...爲什麼你不能只在後臺線程上執行該選擇器?也許我有點密... – lxt 2011-05-20 07:20:29
我開始閱讀關於線程的Apple文檔,它們(沒有)密集。還沒有找到一個簡單的例子。你知道線程嗎?我開始認爲這是不值得的複雜的文件所需要的時間。如果你認爲這是解決方案,我會做,並糾正這篇文章。 – chriscatfr 2011-05-20 11:55:10