連接並插入到php數據庫

我試圖從註冊表格插入數據到數據庫，但當我點擊註冊時，我沒有看到我的數據庫中的任何東西。連接並插入到php數據庫

我真的需要解決這個問題，以便我能夠插入到我的數據庫中。我無法弄清楚問題出在哪裏。非常感謝您的貢獻。

這是我的代碼幫助我。請幫助我。

<?php 

    session_start(); 

    $server = 'localhost'; 
    $users = 'root'; 
    $pass = ''; 
    $dataBase = 'accounts'; 

    $_SESSION['message'] = ''; 

    $mysqli = new mysqli($server, $users, $pass, $dataBase) or die("Not connected"); 

    if($mysqli){ 

     echo 'Connected Successfully'; 
    } 

    if ($_SERVER['REQUEST_METHOD'] == 'POST'){ 


     //The two passwords are equal to each other 
     if($_POST['Password'] == $_POST['ConfirmPassword']){ 

      $username = $mysqli->real_escape_string($_POST["username"]); 
      $email = $mysqli->real_escape_string($_POST['email']); 
      $password = md5($_POST['Password']); //hash password security 
      $phone = $mysqli->real_escape_string($_POST['Number']); 


      $_SESSION['username'] = $username; 

      $sql = "INSERT INTO user (username, email, password, phone) VALUES ('$username','$email','$password','$phone')"; 

      //if the query is correct, then redirect to a welcome.php page. done! 
      if($mysqli->query($sql) === true){ 

       $_SESSION['message'] = "Registration successful! $username is now a member"; 
       header("location: login.php"); 

       echo 'Successfully Registered!'; 

      } 
      else{ 
       $_SESSION['message'] == "Sorry you are not registered, check your field"; 

       } 

      } 

      else{ 
       $_SESSION['message'] == "Passwords do not match!"; 
      } 
     } 
?> 




<body class="bg agileinfo"> 
    <h1 class="agile_head text-center" style="color:#000"> Welcome</h1> 
    <div class="w3layouts_main wrap"> 
    <!--Horizontal Tab--> 
     <div id="parentHorizontalTab_agile"> 
      <ul class="resp-tabs-list hor_1"> 
      <!-- <li>LogIn</li> --> 
       <li>SignUp</li> 
      </ul> 


      <div class="agile_its_registration"> 
        <form action="#" method="post" class="agile_form"> 
         <div class="alert alert-error"><?=$_SESSION['message'] ?></div> 
         <p>Username</p> 
         <input type="text" name="username" required="required" /> 
         <p>Email</p> 
         <input type="email" name="email" required="required" /> 
         <p>Phone Number</p> 
         <input type="text" name="Number" required="required" /> 
         <p>Password</p> 
         <input type="password" name="Password" required="required" id="Password"> 
         <p>Confirm Password</p> 
         <input type="password" name="ConfirmPassword" required="required" id="ConfirmPassword"> 
         <div class="check w3_agileits"> 
          <label class="checkbox w3"><input type="checkbox" name="checkbox" required="required" ><i> </i>I accept the terms and conditions</label> 
         </div> 
         <input type="submit" value="Signup"/> 
         <input type="reset" value="Reset" /> 
        </form> 
       </div> 
      </div> 
     </div> 

</body>

來源

2017-03-16 Umekalu

你說你沒有看到任何東西在你的數據庫，但什麼是SESSION [消息]的執行SQL後的價值？ – Bango

做一個 - printf（「Errormessage：％s \ n」，$ mysqli-> error）;在你的$ sql之後 –

給出名稱提交到提交按鈕和使用

if (isset($_POST['submit'])){ 
}

insted的的

if ($_SERVER['REQUEST_METHOD'] == 'POST'){ 
}

來源

2017-03-16 07:24:03

可能有一個在您的SQL查詢時出現錯誤，只是呼應$sql並運行輸出到你的phpmyadmin。

實施例：

$sql = "INSERT INTO user (username, email, password, phone)  VALUES ('$username','$email','$password','$phone')"; 
echo $sql; 
exit();

然後運行輸出到phpmyadmin。

來源

2017-03-16 07:29:42

您也可以包括PHP_SELF在你的行動：

<?php echo $_SERVER['PHP_SELF']; ?>

，讓你的SQL查詢更改

$sql = "INSERT INTO user (username, email, password, phone) VALUES ('".$username."','".$email."','".$password."','".$phone."')";

希望這有助於！

來源

2017-03-16 07:39:20 Abizz

的變量被當作字符串，所以試試這個：

$sql = "INSERT INTO user (username, email, password, phone)  VALUES ('".$username."','".$email."','".$password."','".$phone."')";

來源

2017-03-16 07:49:06

連接並插入到php數據庫

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