當使用變量嘗試回顯某些內容時出現Ansible問題

Question

當我嘗試使用稍後在curl命令中使用的回聲生成一個curl請求部分時，我有一個Ansible任務。任務如下所示：

- name: Generate requestcode 
shell: echo '{ title: '{{get_hostname.stdout}}', key: '{{ssh_pu_key.stdout}}' }' 
debug: msg: { title: '{get_hostname.stdout}'} 
register: curl_request 

我看到時，我嘗試運行代碼的錯誤是：

ERROR! Syntax Error while loading YAML. 


The error appears to have been in '/root/wifirush.yml': line 54, column 26, but may 
be elsewhere in the file depending on the exact syntax problem. 

The offending line appears to be: 

    - name: Generate requestcode 
    shell: echo '{ title: '{{get_hostname.stdout}}', key: '{{ssh_pu_key.stdout}}' }' 
         ^here 
We could be wrong, but this one looks like it might be an issue with 
missing quotes. Always quote template expression brackets when they 
start a value. For instance: 

    with_items: 
     - {{ foo }} 

Should be written as: 

    with_items: 
     - "{{ foo }}" 

任何建議如何使這項工作？

Answer 1

用途：

shell: echo "{ title{{ ":" }} '{{get_hostname.stdout}}', key {{ ":" }} '{{ssh_pu_key.stdout}}' }"