我使用Hibernate,在我使用org.hibernate.criterion.Example來獲取數據它的工作fine.But,添加布爾屬性,我沒有得到的值。請檢查下面爲什麼org.hibernate.criterion.Example不工作?
@Entity
@Table(name="USER_DETAILS")
public class User extends BaseEntity {
private String name;
private String lname;
private Integer salary;
@Type(type="yes_no")
private boolean newModel;
@Formula("salary*12")
private Long totalSalary;
}
我的代碼後
CriteriaExample.java
public class CriteriaExample {
public static void main(String[] args) {
SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
Session session = sessionFactory.openSession();
User user1 = new User();
user1.setName("Balu");
Criteria cr = session.createCriteria(User.class);
cr .add(Example.create(user1));
List list = cr.list();
System.out.println(list.isEmpty()+".............."+list.size());
}
現在我得到空。但我有10條記錄與斯巴魯的名字在我的數據庫,當我刪除此
@Type(type="yes_no")
private boolean newModel;
我從database.please記錄幫我 這是我的查詢日誌:
select this_.Id as Id1_1_1_, this_.createDate as createDa2_1_1_, this_.updatedOn as updatedO3_1_1_, this_.address_Id as address8_1_1_, this_.lname as lname4_1_1_, this_.name as name5_1_1_, this_.newModel as newModel6_1_1_, this_.salary as salary7_1_1_, this_.salary*12 as formula0_1_, address2_.Id as Id1_0_0_, address2_.createDate as createDa2_0_0_, address2_.updatedOn as updatedO3_0_0_, address2_.streetName as streetNa4_0_0_ from USER_DETAILS this_ left outer join Address address2_ on this_.address_Id=address2_.Id where (this_.name=? and this_.newModel=?)
我沒有在我的例子中的物體,但像上面創建的查詢newModel,並向設定值,還有一件事
當我將布爾值更改爲布爾值時,它工作正常。任何人都可以幫助我
hibernate在日誌中生成的查詢是什麼? – Chaitanya 2014-09-25 16:59:32