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我有一個類，其中我有一個方法名方法（）以JSON字符串的形式返回一個字符串。輸出是::添加Json數據作爲dojogrid的源代碼
[{"ID":1,"Names":"Shantanu"},{"ID":2,"Names":"Mayur"},{"ID":3,"Names":"Rohit"},{"ID":4,"Names":"Jasdeep"},{"ID":5,"Names":"Rakesh"}]
現在這以數據的形式，我想使用Dojo填充Datagrid。而在我的jsp頁面如下::
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@ page import="MyPackage.PopulateTextbox" %>
<%@ page import="java.sql.*" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<style type="text/css">
@import "http://localhost:8080/2_8_2012/js/dojo/resources/dojo.css";
@import "http://localhost:8080/2_8_2012/js/dijit/themes/nihilo/nihilo.css";
</style>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/dojo/1.4/dojo/dojo.xd.js" djConfig="isDebug: false, parseOnLoad: true"></script>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<script type="text/javascript">
dojo.require("dojox.grid.DataGrid");
dojo.require("dojo.data.ItemFileReadStore");
</script>
<script type="text/javascript">
var temp1;
$(document).ready(function() {
PopulateTextbox obj = new PopulateTextbox();
temp1 = obj.method();
});
out.println(temp1);
var storedata={
identifier:"table1",
label:"name",
items: temp1
}
var gridStructure =[{
cells:[
[
{ field: "ID",
name: "ID_Emp",
width: "40%", styles: 'text-align: right;'
},
{
field: "Names",
name: "Name",
width: "40%", styles: 'text-align: right;'
}
]
]
}];
</script>
<title>Dojo Data</title>
</head>
<body class=nihilo>
<div style="width: 400px; height: 300px;">
<div data-dojo-type="dojo.data.ItemFileReadStore" data-dojo-id="countryStoreForGrid" data-dojo-props="data:storeData"></div>
<div id="grid"
data-dojo-type="dojox.grid.DataGrid"
data-dojo-props="store:countryStoreForGrid,
structure:'gridStructure',
queryOptions:{deep:true},
query:{},
rowsPerPage:40">
</div>
</div>
</body>
</html>
我做錯什麼是網頁加載：我將我PopulateTextbox類的一個對象，並調用該函數返回一個JSON字符串的方法，我用它。我在ITEMS下傳遞該字符串：作爲我的Grid數據。這是幹什麼的正確方法？我可以在JavaScript中調用這樣的方法嗎？如果沒有，請給我正確的方法。當我運行運行此頁我得到一個錯誤::
Webpage error details
Message: Expected ';'
Line: 25
Char: 17
Code: 0
URI: http://localhost:8080/2_8_2012/DisplayData.jsp
它我在哪裏寫
PopulateTextbox的obj =新PopulateTextbox同一行（）;
代碼PopulateTextbox.java
package MyPackage;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
import java.util.ArrayList;
import java.util.List;
import net.sf.json.JSONArray;
import net.sf.json.JSONObject;
import com.google.gson.Gson;
public class PopulateTextbox {
Gson gson = new Gson();
JSONObject obj = new JSONObject();
JSONArray arr = new JSONArray();
String temp1;
String temp;
List <String>rowValues = new ArrayList<String>();
List <Integer>rowValues1 = new ArrayList<Integer>();
String[] contactListNames;
Connection con=null;
Statement st=null;
ResultSet rs=null;
public String method(){
try{
String driver = "sun.jdbc.odbc.JdbcOdbcDriver";
Class.forName(driver);
String db = "jdbc:odbc:Practice_Database";
con = DriverManager.getConnection(db,"","");
st = con.createStatement();
String sql = "SELECT Emp_Name,ID FROM EmployeeSearch";
rs = st.executeQuery(sql);
while(rs.next()){
obj.put("ID", rs.getInt("ID"));
obj.put("Names",rs.getString("Emp_Name"));
arr.add(obj);
//obj.add("Name", rs.getString("Emp_Name"));
//rowValues1.add(rs.getInt("ID"));
//rowValues.add(rs.getString("Emp_Name"));
//obj.accumulate("Names",rs.getString("Emp_Name"));
}
//obj.accumulate("ID",rowValues1);
//obj.accumulate("Names",rowValues);
temp1 = arr.toString();
System.out.println(temp1);
contactListNames = (String[]) rowValues.toArray(new String[rowValues.size()]);
temp = gson.toJson(contactListNames);
}catch(Exception e){System.out.println(e);}
/*finally{
try {
if(con!=null)con.close();
} catch (SQLException e) {
e.printStackTrace();
}
try {
if(rs!=null)rs.close();
} catch (SQLException e) {
e.printStackTrace();
}try {
if(st!=null)st.close();
} catch (SQLException e) {
e.printStackTrace();
}
}*/
return temp1;
}
public static void main(String args[])
{
PopulateTextbox obj = new PopulateTextbox();
String temp1= obj.method();
}
}
請幫助。在此先感謝..