我有一個Visual Studio項目,其啓動操作設置爲加載DLL在PowerShell中,像這樣:
<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup Condition="'$(Platform)' == 'Debug|x86'">
<StartAction>Program</StartAction>
<StartProgram>C:\Windows\SysWOW64\WindowsPowerShell\v1.0\powershell.exe</StartProgram>
<StartArguments>-NoProfile -NoExit -Command Add-Type -Path "Foo.dll" -PassThru | Select FullName</StartArguments>
</PropertyGroup>
<PropertyGroup Condition="'$(Configuration)|$(Platform)' == 'Release|x86'">
<StartAction>Program</StartAction>
<StartProgram>c:\windows\system32\windowspowershell\v1.0\powershell.exe</StartProgram>
<StartArguments>-NoProfile -NoExit -Command Add-Type -Path "Foo.dll" -PassThru | Select FullName</StartArguments>
</PropertyGroup>
<PropertyGroup Condition="'$(Configuration)|$(Platform)' == 'Debug|x64'">
<StartProgram>C:\Windows\SysWOW64\WindowsPowerShell\v1.0\powershell.exe</StartProgram>
<StartArguments>-NoProfile -NoExit -Command Add-Type -Path "Foo.dll" -PassThru | Select FullName</StartArguments>
<StartAction>Program</StartAction>
</PropertyGroup>
<PropertyGroup Condition="'$(Configuration)|$(Platform)' == 'Release|x64'">
<StartProgram>c:\windows\system32\windowspowershell\v1.0\powershell.exe</StartProgram>
<StartArguments>-NoProfile -NoExit -Command Add-Type -Path "Foo.dll" -PassThru | Select FullName</StartArguments>
<StartAction>Program</StartAction>
</PropertyGroup>
</Project>
我手編輯的文件到以下刪除冗餘:
<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup '$(Platform)' == 'x86'">
<StartProgram>C:\Windows\SysWOW64\WindowsPowerShell\v1.0\powershell.exe</StartProgram>
</PropertyGroup>
<PropertyGroup Condition="'$(Platform)' == 'AnyCPU' or Condition="'$(Platform)' == 'x64'">
<StartProgram>C:\Windows\System32\WindowsPowerShell\v1.0\powershell.exe</StartProgram>
</PropertyGroup>
<PropertyGroup>
<StartAction>Program</StartAction>
<StartArguments>-NoProfile -NoExit -Command Add-Type -Path "Foo.dll" -PassThru | Select FullName</StartArguments>
</PropertyGroup>
</Project>
現在我想用「$(TargetPath)」之類的東西替換硬編碼的「Foo.dll」。但是,這將評估爲空字符串。下面還決心爲空字符串:
- $(的AssemblyName)
- $(的TargetName)$(TargetExt)
- $(TargetFileName)
設定值<StartArguments>-NoProfile -NoExit -Command Add-Type -Path "$(Platform)" -PassThru | Select FullName</StartArguments>
並創建commandline "C:\Windows\System32\WindowsPowerShell\v1.0\powershell.exe" -NoProfile -NoExit -Command Add-Type -Path "x64" -PassThru | Select FullName
我實際上正在通過Microsoft.common.targets尋找。也許只是重新導入它將工作。但是,我不希望$(TargetDir)我想要的名稱的DLL。 –
這實際上取決於什麼樣的環境.user文件加載到VS啓動時。不幸的是,我找不到任何有關信息。我嚴重懷疑它會是相同的\相似的msbuild上下文用於生成項目。你可能會嘗試將你的原始.proj文件包含到.user中 - 然後它應該加載所有的導入,並且在評估階段之後,你應該在$(AssemblyName)中擁有合適的文件名,但是這是一種非常髒的方式,可以使用imo。 PS謝謝你的語法修復。 –