該代碼是在C + + 14簡單特里實現。當執行以下錯誤add("name")
功能彈出式:EXC_BAD_ACCESS(碼= 1,地址= 0×20))EXC_BAD_ACCESS在unordered_map
遵循以下一些調試圖像:
遵循下面的代碼:
struct TrieNode {
string value;
unordered_map<char, TrieNode *> children = {};
};
class Trie {
public:
TrieNode *root = new TrieNode;
TrieNode *find(string query);
int countPartialFind(string query);
void add(string value);
private:
void add(string value, TrieNode *node);
TrieNode *createNewNode(string &value, int counter, unordered_map<char, TrieNode *> &children);
void add(string value, int counter, TrieNode *node);
TrieNode *findNode(char query, unordered_map<char, TrieNode *> &children);
};
TrieNode *Trie::find(string value) {
TrieNode *tmpNode = root;
for (int counter = 0; counter < value.length(); counter++) {
tmpNode = findNode(value[counter], tmpNode->children);
if (tmpNode == NULL) {
return NULL;
}
}
return tmpNode;
}
int Trie::countPartialFind(string query) {
TrieNode *matchNode = find(query);
if (matchNode == NULL) {
return 0;
}
return matchNode->children.size();
}
void Trie::add(string value, int counter, TrieNode *node) {
for (; counter < value.length(); counter++) {
node = findNode(value[counter], node->children);
if (node == NULL) {
node = createNewNode(value, counter, node->children);;
}
}
}
TrieNode *Trie::findNode(char query, unordered_map<char, TrieNode *> &children) {
unordered_map<char, TrieNode *>::const_iterator search = children.find(query);
if (search == children.end()) {
return NULL;
}
return search->second;
}
TrieNode *Trie::createNewNode(string &value, int counter, unordered_map<char, TrieNode *> &children) {
TrieNode *newNode = new TrieNode;
newNode->value = value.substr(0, counter + 1);
char tmp = value[counter];
children[tmp] = newNode;
return newNode;
}
void Trie::add(string value) {
if (value.length() == 0) { return; }
int counter = 0;
TrieNode *tmpNode = findNode(value[counter], root->children);
if (tmpNode == NULL) {
tmpNode = createNewNode(value, counter, root->children);
}
add(value, ++counter, tmpNode);
}
這個問題應該是微不足道的,但我不能理解它。感謝您的幫助,它還有其他可以完成的優化或代碼設計,請讓我知道。
您是否通過與調試程序的代碼踩找到該行實際上觸發異常? – NathanOliver
是的,但沒有抓住它,對不起,錯誤可能是如此愚蠢,然後我會感到羞恥。 –