正則表達式：從2個標籤中刪除所有內容

Question

我有這種腳本。我想選擇/刪除<script type='text/javascript'>所有腳本</script>

<script type='text/javascript'> window['__wavt'] = 'AOuZoY7C5YW0NbvyHBM2AbUwwOO7gpMxsA:1495265533940';_WidgetManager._Init('//www.blogger.com/rearrange?blogID\x3d1126651761205083490','11-povesti-in-11-minute-la-11even.html'/*tpa=http://www.sena.com/2012/05/11-povesti-in-11-minute-la-11even.html*/,'1126651761205083490'); 
_WidgetManager._SetDataContext([{'name': 'blog', 'data': {'blogId': '1126651761205083490', 'title': 'Richie`s Day', 'url': 'my-link.html'/*tpa=http://www.sena.com/2012/05/mylink.html*/, 'canonicalUrl': </script> 

無論如何，我做了2正則表達式，但沒有工作：

(<script type='text/javascript'>)[\s\S]*?(</script>[\s\S]*?

(?-s)^.*(<script type='text/javascript'>)(?s).*?(?-s)(</script>).*(\r\n|\z)

Answer 1

肯定的是，我找到了答案：

(?s)(<script type='text/javascript).*?(?-s)(</script>)

或

^.*(?s)(<script type='text/javascript).*?(?-s)(</script>).*$

所以，對於任何人，

(?s)(SELECT_FROM-PART-ONE).*?(?-s)(TO-PART-TWO)

或

^.*(?s)(SELECT_FROM PART-ONE).*?(?-s)(TO_PART_TWO).*$